restructuring the repository

README.md

@@ -1,13 +1,73 @@
 ---
 configs:
-- config_name: final_dataset
-  data_files: "data/final_dataset.csv"
-- config_name: evaluation_dataset
-  data_files: "data/evaluation_dataset.csv"
-- config_name: testset
-  data_files: "data/testset.csv"
-- config_name: train
-  data_files: "data/train.csv"
+- config_name: v1_bea
+  data_files: "data/v1_bea/*.csv"
+- config_name: v2_sigcse
+  data_files: "data/v2_sigcse/*.csv"
+- config_name: v3
+  data_files: "data/v3/*.csv"
 ---
 
 # Socratic benchmark
+
+## Dataset Description
+
+The Socratic benchmark is a dataset of tutor-student interactions released by Erfan Al-Hossami et al. (see citations bellow). The dataset released here on HuggingFace for easier training and evaluation of feedback/tutor language models.  
+
+
+## Dataset structure
+
+The dataset structure matches the repository structure as released in the [GitHub repo](https://github.com/taisazero/socratic-debugging-benchmark). Each subset corresponds to a version, and each split a subrepo in the corresponding version folder.
+
+## Languages
+
+The assignments were written in Python. 
+
+
+### Citation Information
+
+All credits should be attributed to the original authors:
+
+```
+@inproceedings{al-hossami-etal-2023-socratic,
+    title = "Socratic Questioning of Novice Debuggers: A Benchmark Dataset and Preliminary Evaluations",
+    author = "Al-Hossami, Erfan  and
+      Bunescu, Razvan  and
+      Teehan, Ryan  and
+      Powell, Laurel  and
+      Mahajan, Khyati  and
+      Dorodchi, Mohsen",
+    booktitle = "Proceedings of the 18th Workshop on Innovative Use of NLP for Building Educational Applications (BEA 2023)",
+    month = jul,
+    year = "2023",
+    address = "Toronto, Canada",
+    publisher = "Association for Computational Linguistics",
+    url = "https://aclanthology.org/2023.bea-1.57",
+    pages = "709--726",
+    abstract = "Socratic questioning is a teaching strategy where the student is guided towards solving a problem on their own, instead of being given the solution directly. In this paper, we introduce a dataset of Socratic conversations where an instructor helps a novice programmer fix buggy solutions to simple computational problems. The dataset is then used for benchmarking the Socratic debugging abilities of GPT-based language models. While GPT-4 is observed to perform much better than GPT-3.5, its precision, and recall still fall short of human expert abilities, motivating further work in this area.",
+}
+```
+```
+@inproceedings{al-hossami-etal-2024-can,
+author = {Al-Hossami, Erfan and Bunescu, Razvan and Smith, Justin and Teehan, Ryan},
+title = {Can Language Models Employ the Socratic Method? Experiments with Code Debugging},
+year = {2024},
+isbn = {9798400704239},
+publisher = {Association for Computing Machinery},
+address = {New York, NY, USA},
+url = {https://doi.org/10.1145/3626252.3630799},
+doi = {10.1145/3626252.3630799},
+abstract = {When employing the Socratic method of teaching, instructors guide students toward solving a problem on their own rather than providing the solution directly. While this strategy can substantially improve learning outcomes, it is usually time-consuming and cognitively demanding. Automated Socratic conversational agents can augment human instruction and provide the necessary scale, however their development is hampered by the lack of suitable data for training and evaluation. In this paper, we introduce a manually created dataset of multi-turn Socratic advice that is aimed at helping a novice programmer fix buggy solutions to simple computational problems. The dataset is then used for benchmarking the Socratic debugging abilities of a number of language models, ranging from fine-tuning the instruction-based text-to-text transformer Flan-T5 to zero-shot and chain of thought prompting of the much larger GPT-4. The code and datasets are made freely available for research at the link below.},
+booktitle = {Proceedings of the 55th ACM Technical Symposium on Computer Science Education V. 1},
+pages = {53–59},
+numpages = {7},
+keywords = {benchmark dataset, debugging, language models, socratic dialogue},
+location = {<conf-loc>, <city>Portland</city>, <state>OR</state>, <country>USA</country>, </conf-loc>},
+series = {SIGCSE 2024}
+}
+
+
+
+### Contributions
+
+[More Information Needed]

data/raw/v1_bea/evaluation_dataset/0_0_fibonacci_conversational_thread_1.txt

@@ -0,0 +1,119 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+The student has a misconception about for loop ranges. The student also struggles to explain their code. The student knows how to use the debugger.
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I can use the debugger perhaps.
+	<alt>I can add print statements.
+	<alt>I'm not really sure can you suggest a way?
+Assistant: Let's first examine the values of `i`. How many times in total does the for loop iterate?
+User: Using the debugger I notice that the for loop iterates 5 times when `n` is  5 and the values of `n` range from 0 to 4 or `n - 1`. I thought it loops from 1 to `n`.
+Assistant: If your for loop is iterating more than you expected how might that impact the returned value?
+	<alt>Good. Let's go through the debugger again and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: If it iterates one more time than I expected then it might be going to the next Fibonacci term in the sequence. So in our case 8 as opposed to 5!
+	<alt>Not really sure, maybe need to step through it to see how it affects the returned term.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n - 1):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all looks good! Thank you so much!
+Assistant: You are welcome. Let me know if I can be of any further assistance.
+User: Thank you!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/0_0_fibonacci_conversational_thread_2.txt

@@ -0,0 +1,141 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to `0` not `1`? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I'm not really sure can you suggest a way?
+	<alt>I can add print statements.
+	<alt>I can use the debugger perhaps.
+Assistant: Have you thought about adding a print statement to print the value of `i` at each iteration?
+	<alt>Have you considered using the debugger to track the value of `i` at each iteration?
+User: Ah yes good idea. Let me do that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(i)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's examine the values of `i`. How many times in total does the for loop iterate?
+User: Observing the terminal output, I notice that the for loop iterates 5 times when `n` is  5 and the values of `n` range from 0 to 4 or `n - 1`. I thought it loops from 1 to `n`.
+Assistant: If your for loop is iterating more than you expected how might that impact the returned value?
+	<alt>Good. Let's go through the debugger again and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: If it iterates one more time than I expected then it might be going to the next Fibonacci term in the sequence. So in our case 8 as opposed to 5!
+	<alt>Not really sure, maybe need to step through it to see how it affects the returned term.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time and remove the print statement. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n - 1):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all looks correct! Thank you so much!
+Assistant: You are welcome. Let me know if I can be of any further assistance.
+User: Thank you!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/0_0_fibonacci_conversational_thread_3.txt

@@ -0,0 +1,199 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to 0, not 1? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I'm not really sure can you suggest a way?
+	<alt>I can add print statements.
+	<alt>I can use the debugger perhaps.
+Assistant: Have you thought about adding a print statement to print the value of `i` at each iteration?
+	<alt>Have you considered using the debugger to track the value of `i` at each iteration?
+User: Ah yes good idea. Let me do that. 
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(n)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's examine the values of `i`. How many times in total does the for loop iterate?
+User: Observing the terminal output, I notice that `i` is always 5 when `n` is 5. That doesn't make sense.
+Assistant: Are you sure that you are looking at the values of `i`? Examine line 12.
+	<alt>What variable are you printing on line 12?
+User: Oh whoops! Let me fix that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(i)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's look at the terminal output. How many times does the for loop iterate?
+User: Observing the terminal output, I notice that the for loop iterates 5 times when `n` is  5, and the values of `n` range from 0 to 4 or `n - 1`.
+Assistant: Good. Can you identify other variables that might be important for us to track to identify the issue?
+	<alt>Let's add a print statement to print the values of `a`, `b` as well at each iteration to verify that. After executing the code what do you notice?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>What would happen to the returned Fibonacci term if the for loop iterates 6 times?
+User: I think it would be good to track the variables `a` and `b` since I return `b` in the end and `a` is used to compute `b`.
+Assistant: Good. What do you think would be a good way for us to track the values of `a` and `b`?
+	<alt>Let's add a print statement to print the values of `a`, `b` as well at each iteration to verify that. After executing the code what do you notice?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: I think I can add a print statement for these variables inside the for loop!
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(f"a: {a}\tb: {b}\t i: {i}")
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Good. What do you observe about the values of `b` as the loop iterates?
+User: Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.
+Assistant: What do you notice about the last value of `b`?
+User: Oh! It's 8 which is what I am returning instead of 5! But why is that?
+Assistant: How was `b` computed in the final iteration of the for loop?
+User: I think `b` was 5 and `a` was 3 so  `b = 3 + 5` which is 8. Not sure how to get it to return 5 though.
+Assistant: What would happen to the returned Fibonacci sequence if the for loop iterates 6 times?
+	<alt>Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+User: Hm. I think it would `b = 5 + 8` which is 13 the next number in the Fibonacci sequence.
+Assistant: Do you notice a relationship between the number of for loop iterations and the Fibonacci term returned?
+User: Yes! I do think that the more the loop iterates the larger the Fibonacci term is returned. Maybe my for loop is iterating more than it should.
+Assistant: Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code and remove my print statement.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all is correct thank you so much!
+Assistant: You are welcome. Let me know if I can help with anything else!
+User: Thank you so much!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/0_0_fibonacci_socratic_dialogue.txt

@@ -0,0 +1,158 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+The student is a beginner to an intermediate programmer who is familiar with basic programming concepts but may still struggle with some details, such as loop iteration.
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+	<alt>I am not sure. Can you help?
+	<alt>I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.
+Assistant: Good. Can you explain your for loop on line 11?
+	<alt>What specifically about your for loop on line 11 might be causing the issue?
+	<alt>Good. Can you describe how many times the for loop iterates on line 11?
+	<alt>Good. How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Good. What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Good. Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+	<alt>It loops `n` times
+	<alt>Not really sure how to describe it.
+Assistant: Good, let's examine the loop together. How can we monitor the values of `a`, `b`, and `i` during the loop?
+	<alt>What are the values of `a` and `b` in each iteration?
+	<alt>What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration. After executing the code what do you notice?
+User: I'm not really sure can you suggest a way?
+	<alt>I can use the debugger!
+	<alt>I can add print statements.
+Assistant: Have you considered inserting a print statement after line 12 to output the 3 variables?
+	<alt>Have you considered using the debugger?
+User: Aha! Good idea! Perfect let me do that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.   b = 1
+11.   for i in range(0, n):
+12.      temp = b
+13.      print(f"a: {a}\tb: {b}\t i: {i}")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's look at the outputs what do you observe?
+User: I observe that `b` starts at 1 and `a` at  0 in the first iteration. `a` basically stores the value of `b` in the previous iteration.  Ultimately, at  `i = 0` `b = 0 + 1` then  at `i = 1` it is `b = 1 + 1` then at `i = 2` it is `b = 1 + 2` then at `i = 3` it is `b = 2 + 3` and at last  when `i = 4` it is `b = 3 + 5` returning 8.
+	<alt>It seems like the for loop is iterating one extra time. we want it to stop at `i = 3` where `b` is 5.
+	<alt>Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.
+Assistant: What do you notice about the value of `b`? Does it ever hold the correct Fibonacci term?
+	<alt>Good. Can you identify the point at which the loop should stop to get the correct Fibonacci number?
+User: We would want the for loop to stop at `i = 3` and return `b` as 5, but it iterates one more time since `3 <  5` which is the value of `n`.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      print(f"a: {a}\tb: {b}\t i: {i}")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Good work. Don't forget to remove the print statement!
+User: Ah yes! Thank you so much for your help!
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: You are welcome. Let me know if you have any further questions.
+User: Thanks again! Goodbye!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/0_2_fibonacci_conversational_thread_1.txt

@@ -0,0 +1,91 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello. I need help with my code.
+	<alt>Hello! I need help on this my code is failing the first test case.
+Assistant: Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?
+	<alt>Can you walk me through your code step by step given that `n` is 0?
+	<alt>Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?
+	<alt>Can you describe the issue you are facing? Is your code failing any test cases?
+	<alt>Let's look at the `fibonacci` problem description. Given that `n` is 0. What should the `fibonacci` function return?
+User: Hm... I've never seen assignment being done like this before. I presume it would be a compiler error?
+	<alt>I think the value of `y` will be 0 because `x` is 0 and 0 < 0 is `False` so `else 0` will execute.
+Assistant: Let's verify that. Can you open a Python terminal and type in `x = 0` then on a new line `y = 1 if x < 0 else 0`. What do you observe?
+User: Ah. It works! I learned something new today.
+Assistant: What do you think the value of `y` is?
+User: I think the value of `y` will be 0 because `x` is 0 and 0 < 0 is `False` so `else 0` will execute.
+Assistant: Good. Let's look at your `fibonacci` function. Given that `n` is 0. Can you walk me through your code step by step?
+	<alt>Let's verify that. Can you print `y`? What do you observe?
+	<alt>Good. Let's look at your `fibonacci` function. Given that `n` is 0. What does the if statement on line 2 evaluate to?
+	<alt>Good. Let's look at the `fibonacci` problem description. Given that `n` is 0. What should the `fibonacci` function return?
+User: On line 2 `n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of "OOPS". I see the issue is the condition on line 2. Let me fix it.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good. Did you try running your code through all the test cases?
+User: Yes. Thank you very much for your help!
+Assistant: You're welcome.
+</dialogue>

data/raw/v1_bea/evaluation_dataset/0_2_fibonacci_socratic_dialogue.txt

@@ -0,0 +1,78 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I need help on this my code is failing the first test case.
+	<alt>Hello. I need help with my code.
+Assistant: Can you walk me through your code step by step given that `n` is 0?
+	<alt>Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?
+	<alt>Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?
+User: `n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of "OOPS". I see the issue is the condition on line 2. Let me fix it.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</code>
+Assistant: Good. Did you try it for all the unit tests?
+User: Yes I have. Thank you so much for your help!
+Assistant: You're welcome!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/0_5_fibonacci_conversational_thread_1.txt

@@ -0,0 +1,79 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: The previous two positions.
+	<alt>The numbers at positions n - 1 and n - 2.
+	<alt>The numbers at positions n - 1 and n - 2. Ah, now I see, I made a mistake on line 7, I used the wrong positions there. Let me fix it... It works now, thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n-1) + fibonacci(n-2)
+
+</code>
+Assistant: Correct. Since the current position is `n`, what are the previous two positions?
+	<alt>That is correct. Looking at your code, does it really add the Fibonacci numbers at the previous two positions?
+User: Ah, now I see what the problem is. The code on line 7 adds the number at the current position, instead of positions `n - 1` and `n - 2`. Let me fix that... it works! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+</code>
+Assistant: You are welcome, happy to help.
+</dialogue>

data/raw/v1_bea/evaluation_dataset/0_5_fibonacci_conversational_thread_2.txt

@@ -0,0 +1,84 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: Can you explain what infinite recursion means?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: Infinite recursion means that the function calls itself without ever stopping.
+	<alt>I am not sure, can you explain infinite recursion to me?
+Assistant: Correct. Where in the code does the function call itself?
+	<alt>Good. Given that the problem is caused by the function calling itself forever, where in the code do you think the problem is?
+User: It is on line 7.
+Assistant: Correct. There are two recursive calls there, can you figure out which of them leads to infinite recursion?
+	<alt>Correct. So, when the function is called as `fibonacci(n)`, if it gets to line 7 it calls `fibonacci(n)` again, and if that is completed it then calls `fibonacci(n - 1)`. Do you see why this leads to infinite recursion?
+User: Ah, I see. It is the call to `fibonacci(n)`, because `fibonacci(n)`calls `fibonacci(n)`which will again call `fibonacci(n)`, forever.
+	<alt>Ah, I see, it is the call to `fibonacci(n)`. I made a mistake, I should have called fibonacci for `n - 1` and `n - 2`. Let me do that ... it works! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+</code>
+Assistant: Good! That means the code on line 7 is not correct. Can you look at the problem description to see how the Fibonacci number at position `n` needs to be computed and fix your code?
+	<alt>Good! Can you fix the code in line 7 so that it implements what is in the problem description?
+User: Ah, I see now, the previous two numbers are at positions `n - 1` and `n - 2`. Let me fix that... it works now! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+</code>
+Assistant: You are welcome!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/0_5_fibonacci_conversational_thread_3.txt

@@ -0,0 +1,65 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>Can you explain what infinite recursion means?
+User: We get the Fibonacci number for `n + 1`. Ah, I see what the problem is, I used the wrong inputs in the recursive calls. Let me fix that... it works, it passes all the tests now. Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+</code>
+	<alt>We get the Fibonacci number for `n + 1`.
+Assistant: You're welcome!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/0_5_fibonacci_socratic_dialogue.txt

@@ -0,0 +1,88 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: I believe it is line 7, because that is the line that is executed when `n` is larger than 2.
+Assistant: That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?
+	<alt>Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?
+	<alt>Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?
+User: Well, the function is called recursively to compute `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+
+</code>
+	<alt>The call `fibonacci(n)`.
+Assistant: So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?
+	<alt>Do you see now why infinite recursion happens?
+	<alt>So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?
+User: Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+
+</code>
+Assistant: Great, your program now works as expected!
+User: Thank you so much!
+Assistant: You are welcome!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/10_39_xnglxsh_conversational_thread_1.txt

@@ -0,0 +1,90 @@
+<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH("My name is John!") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, "x")
+6.      else:
+7.           sen.replace(i, "X")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH("My name is John!") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I wrote a lot of code and nothing is working.
+Assistant: I'm here to help. Can you describe the problem you are having?
+     <alt>Can you walk me through your code line by line?
+     <alt>Let's start with a simple example. What is the output of your code when you run it with the input "English"?
+     <alt>What does the `.replace()` method do?
+     <alt>What does the `.swapcase()` method do?
+User: I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?
+Assistant: What are some reasons it could be staying the same?
+     <alt>What does the `.replace()` method do and does it modify the original string?
+     <alt>What does the `.swapcase()` method do and does it modify the original string?
+User: I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.
+	<alt>If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.
+Assistant: Let's test each of these separately. How can you check whether the methods are being called?
+User: One way I could check this is by adding `print` statements right before the methods to make sure I'm reaching those parts of the code. It looks like I'm reaching each part, but the sentence isn't changing. I think I'm not using these methods properly.
+<code>
+ def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           print("here1", sen)
+           sen.replace(i, "x")
+      else:
+           print("here2", sen)
+           sen.replace(i, "X")
+  print("here3", sen)
+  sen.swapcase()
+  return sen
+
+</code>
+Assistant: Is there an easy way to modify your code to verify whether your code is modifying the original string?
+     <alt>What makes you think that you are using the methods incorrectly?
+     <alt>Have you considered printing the output of the method calls to see if they are changing the string, for example, `print(sen.replace(i, "x"))`?
+     <alt>Have you considered assigning the output of the method calls to a variable?
+     <alt>Where can you learn more about how `.replace()` and `.swapcase()` work and how they are used?
+User: Hm, I guess I can just assign `sen` the output of the method calls, in case they don't do in-place changes. That works!
+     <alt>I could also just print the output of the method calls to see if they are changing the string.
+<code>
+ def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           sen = sen.replace(i, "x")
+      else:
+           sen = sen.replace(i, "X")
+  sen = sen.swapcase()
+  return sen
+
+</code>
+Assistant: Great! let me know if you need more help.
+</dialogue>

data/raw/v1_bea/evaluation_dataset/10_39_xnglxsh_socratic_dialogue.txt

@@ -0,0 +1,75 @@
+<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH("My name is John!") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, "x")
+6.      else:
+7.           sen.replace(i, "X")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH("My name is John!") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I wrote a lot of code and nothing is working.
+Assistant: I'm here to help. Can you describe the problem you are having?
+     <alt>Can you walk me through your code line by line?
+     <alt>Let's start with a simple example. What is the output of your code when you run it with the input "English"?
+     <alt>What does the `.replace()` method do?
+     <alt>What does the `.swapcase()` method do?
+User: I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?
+Assistant: What are some reasons it could be staying the same?
+     <alt>What does the `.replace()` method do and does it modify the original string?
+     <alt>What does the `.swapcase()` method do and does it modify the original string?
+User: If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.
+	<alt>I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.
+Assistant: Let's open up the Python terminal and try running `sen = "To"` and then `sen.replace("o", "X")`. What do you observe?
+     <alt>Let's open up the Python terminal and try running `sen = "English"` and then `sen.swapcase()`. What do you observe?
+User: Ok, I tried that, and it looks like it returns the modified string I expect `TX`.
+     <alt>Ok, I tried that, and it looks like it returns the modified string I want `x` when I run it but after that when I print `sen` after that it shows `To` again. Maybe this means that the change is being applied, but not stored anywhere. I will assign the output of the string methods to `sen`.
+Assistant: Good. Now let's try running `sen = sen.replace("o", "X")` and then `print(sen)`. What do you observe?
+     <alt>Good. Now let's try running `sen = sen.swapcase()` and then `print(sen)`. What do you observe?
+User: Ah. It looks like the string methods don't modify the original string. They return a new string with the changes applied. I need to assign the output of the string methods to `sen` so that the changes are saved. Let me try that.
+<code>
+def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           sen = sen.replace(i, "x")
+      else:
+           sen = sen.replace(i, "X")
+  sen = sen.swapcase()
+  return sen
+
+</code>
+Assistant: That looks good! Why do you think it worked?
+User: It looks like applying the method to a variable doesn't save the output anywhere. I guess they create new strings instead of modifying the original string. We need to assign it to the original variable so that the new output is saved.
+Assistant: Good work!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/11_40_palindrome_conversational_thread_1.txt

@@ -0,0 +1,68 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I have a compiler error here.
+Assistant: Ok, what error do you see?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: It's giving me an error on my equality operator use.
+Assistant: I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: I use the `=` operator.
+Assistant: What are you trying to do in line 5?
+	<alt>How would you check if  two variables `x` and `y` are equivalent?
+User: Ah I see the problem now. I should use `==` instead of equals to check for equality. Let me edit my code.
+	<alt>I am trying to check if `rev_string` is equal to `string`.
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+
+</code>
+Assistant: Looks good! Does it pass all the test cases now?
+User: Yes it does! Thank you so much!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/11_40_palindrome_socratic_dialogue.txt

@@ -0,0 +1,73 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I have a compiler error here.
+Assistant: Ok, what error do you see?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: It's giving me an error on my equality operator use.
+Assistant: I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: I use the `=` operator.
+Assistant: What are you trying to do in line 5?
+	<alt>How would you check if  two variables `x` and `y` are equivalent?
+User: I am trying to check if `rev_string` is equal to `string`
+	<alt>Ah I see so I should use `==` instead of equals to check for equality. Let me edit my code.
+Assistant: You used `=` for variable assignment. Shouldn't there be a different operator for equality?
+	<alt>Let's check the documentation. What is the operator for equality?
+	<alt>Are you sure that `=` checks for equality? How can we verify that?
+	<alt>If we were to assume that `=` checks for equality, would that be consistent with the error you noticed?
+User: I thought that they were for both purposes but after checking, I think the `==` operator is used to check for equality in Python.
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+
+</code>
+Assistant: Looks good!
+User: Thank you so much!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/12_41_reversing_a_list_conversational_thread_1.txt

@@ -0,0 +1,68 @@
+<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list(["Hi", "Hello", "Goodbye"]) => ["Goodbye", "Hello", "Hi"]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list(["Hi", "Hello", "Goodbye"]) == ["Goodbye", "Hello", "Hi"]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to reverse the elements of a list but it's not working.
+Assistant: Can you describe how you're trying to reverse the list?
+	<alt>Can you describe the problem you're having in more detail?
+	<alt>Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?
+	<alt>Let's start with a warm-up question. What does the slicing operator `[-1:]` do?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Where can you learn more about how to reverse a list?
+User: Sure, I used the `[-1:]` slicing operator.
+Assistant: Can you describe what the `[-1:]` slicing operator does?
+	<alt>How do you think this reverses the list?
+	<alt>Do you notice a pattern in your function's outputs?
+	<alt>How does slicing work in Python?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+User: The `[-1:]` slicing operator should return a list in reverse order.
+	<alt>I think it should return a list in reverse order but it's returning the last element of the list instead.
+Assistant: What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Let's run your code through all the test cases. Do you notice a pattern in your function's outputs?
+	<alt>Let's open the terminal and run `[1, 2, 3][-1:]`. What do you observe?
+	<alt>Let's start with a simpler problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+User: It returns `[3]` instead of `[3, 2, 1]`. Hm... it seems to be returning the last element of the list instead of the whole list in reverse order.
+Assistant: Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?
+	<alt>Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+User: For an input list `a`, we can get every other element by using `a[::2]`. So `a[::2]` should return `[1, 3]`.
+Assistant: Good. Given that `[-1:]` returns the last element in the list, how do we combine using `::` with `[-1:]` to get every element in reverse order?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+	<alt>Good. `::2` gives us every other element and `[-1:]` gives us the last element. How can we get every element in reverse order?
+User: Oh, I see. We can just get every element of the list in increments of -1. So `a[::-1]`. I'll update my code. It looks like it's working now
+<code>
+ def reverse_list(lst):
+    return lst[::-1]
+
+</code>
+Assistant: Great! Let me know if you run into any other problems!
+User: Thanks!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/12_41_reversing_a_list_socratic_dialogue.txt

@@ -0,0 +1,59 @@
+<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list(["Hi", "Hello", "Goodbye"]) => ["Goodbye", "Hello", "Hi"]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list(["Hi", "Hello", "Goodbye"]) == ["Goodbye", "Hello", "Hi"]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to reverse the elements of a list but it's not working.
+Assistant: Can you describe how you're trying to reverse the list?
+	<alt>Can you describe the problem you're having in more detail?
+	<alt>Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?
+	<alt>Let's start with a warm-up question. What does the slicing operator `[-1:]` do?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Where can you learn more about how to reverse a list?
+User: Sure, I used the `[-1:]` slicing operator.
+Assistant: Can you describe what the `[-1:]` slicing operator does?
+	<alt>How do you think this reverses the list?
+	<alt>Do you notice a pattern in your function's outputs?
+	<alt>How does slicing work in Python?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+User: I think it should return a list in reverse order but it's returning the last element of the list instead.
+	<alt>The `[-1:]` slicing operator should return a list in reverse order.
+Assistant: Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+	<alt>Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+    <alt>Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?
+User: I see. Got it. I think I need to use the `[::-1]` slicing operator or I can use the `reversed()` method. I'll update my code. It looks like it's working now.
+<code>
+ def reverse_list(lst):
+    return lst[::-1]
+
+</code>
+Assistant: Great! Let me know if you run into any other problems!
+User: Thanks!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/14_43_used_twice_conversational_thread_1.txt

@@ -0,0 +1,87 @@
+<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice("hello", "l") => True
+isTwice("hello", "o") => False
+isTwice("hello", "h") => False
+isTwice("", "e") => False
+isTwice("I'm a string!", " ") => True
+isTwice("Hey, I'm a string!", " ") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice("hello", "l") == True
+assert isTwice("hello", "o") == False
+assert isTwice("hello", "h") == False
+assert isTwice("", "e") == False
+assert isTwice("I'm a string!", " ") == True
+assert isTwice("Hey, I'm a string!", " ") == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! This code isn't working. Can you help?
+Assistant: Let's talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `"False"` is?
+	<alt>First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?
+	<alt>It seems that you have a `NameError` error in your code. Are you able to find where this error is?
+	<alt>Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?
+User: Well, boolean and Strings are different data types. Booleans have a true or false value, and Strings are just written words.
+	<alt>a boolean true is written like `bool = True`, whereas a String variable is written as str = "True."
+	<alt>I don't think there is a difference. I think both boolean "true" and String "true" looks the same when you write the code. For example, str = true and bool = true.
+Assistant: Let's try an example. How would you declare a string variable "str" and initialize it to the value "true?"
+	<alt>What are the two possible values of a boolean variable in Python?
+User: String str = "true";
+	<alt>Wouldn't you want to use a boolean variable for that instead?
+	<alt>String str = true;
+	<alt>str = true
+	<alt>String str = True;
+Assistant: That's right! Now, how would you declare a boolean variable `bool` and initialize it to false?
+User: boolean bool = false;
+	<alt>boolean bool = False;
+	<alt>boolean bool = "False";
+	<alt>I don't see that we are using boolean variables in the code.
+Assistant: Programming languages are very sensitive to syntax. For example, String variables require the use of quotations around their input. Can you think of any similar constraints to boolean inputs?
+	<alt>Try looking at the Python documentation. Can you find the section where they describe the use of Boolean variables? How does it compare to what you wrote here?
+	<alt>Let's try that in the Python terminal. What happens when you type `bool = false`?
+User: Oh, I see. I was writing `bool = true` when I should have been writing `bool = True`. I am missing a capitalization.
+	<alt>I should be using 0 and 1 instead of false and true.
+	<alt>I can't think of any constraints.
+Assistant: Good! Can you find where you made this mistake in your code?
+	<alt>How can you edit your code to fix this error?
+User: Yes, I found it. I'm going to show you the changed code now.
+<code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return True
+9.  else:
+10.    return False
+
+</code>
+Assistant: Good work! Looks like you did it.
+User: Thank you!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/14_43_used_twice_socratic_dialogue.txt

@@ -0,0 +1,83 @@
+<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice("hello", "l") => True
+isTwice("hello", "o") => False
+isTwice("hello", "h") => False
+isTwice("", "e") => False
+isTwice("I'm a string!", " ") => True
+isTwice("Hey, I'm a string!", " ") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice("hello", "l") == True
+assert isTwice("hello", "o") == False
+assert isTwice("hello", "h") == False
+assert isTwice("", "e") == False
+assert isTwice("I'm a string!", " ") == True
+assert isTwice("Hey, I'm a string!", " ") == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I wrote this code and it isn't working. can you help me?
+Assistant: First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?
+	<alt>It seems that you have a `NameError` error in your code. Are you able to find where this error is?
+	<alt>Let's talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `"False"` is?
+	<alt>Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?
+User: I have a syntax error. My code won't even compile.
+	<alt>I think it's a runtime error because it just stopped running.
+	<alt>Can you tell me what the different types of errors are? I don't remember.
+	<alt>It's a logic error, I think. That's the one that is the result of a grammatical error, right?
+Assistant: I see! Let's try to solve a simpler problem. Can you write a code snippet of assigning `True` to a boolean variable called 'var'?
+	<alt>Can you write a code snippet of assigning `False` to a boolean variable called 'var'?
+	<alt>Where is the syntax error located in your code? You look for the line number.
+	<alt>How do you know that it is a syntax error? What are the different types of errors?
+User: `var = True`
+	<alt>`var = true`
+	<alt>var = 1
+	<alt>var = "True"
+Assistant: That's right. Is this what you wrote in your code on line 8?
+	<alt>That's right. Can you look back at where you use boolean variables and see if you used the correct syntax?
+	<alt>Can you point out in your code where you use boolean variables?
+User: No it isn't. I see. Well... the is not a boolean variable anymore. The value you assign to the code determines what kind of data type it is. Since I did not write 'True' in this exact format, I imagine that the program had interpreted the value as a variable that hasn't been initialized instead.
+	<alt>The code would get a syntax error and it wouldn't run.
+	<alt>I'm not sure what you are asking.
+Assistant: That's right! How can you modify your `isTwice` function now to fix this error?
+User: Oh! I found it! I was returning all lowercase True and False values! I will fix it.
+<code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return True
+9.  else:
+10.    return False
+
+</code>
+Assistant: Looks like it works now. Good job!
+User: Thanks!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/15_44_sequential_search_conversational_thread_1.txt

@@ -0,0 +1,68 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: We should return the index of `x` in `seq`.
+Assistant: Good. How do you find the index of `x` in a list `seq`?
+	<alt>Good. Now, looking at your code, does it ever return an index `i` such that the element at that index is equal to `x`?
+	<alt>Good. If the current index is `i`, how do you determine if the element at position `i` in the list `seq` is equal to `x`?
+User: I go through all possible indexes, starting at 0, and check of `seq[i]` is equal to `x`.
+Assistant: Good. Can you add code to do that?
+User: Let me try... I did it and it works now. Thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x == seq[i]:
+4.      return i
+5.    if x < seq[i]:
+6.      return i
+7.  return len(seq)
+
+</code>
+	<alt>I did it, and now the first test case works well, but the others don't work anymore.
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x == seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, happy to help!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/15_44_sequential_search_conversational_thread_2.txt

@@ -0,0 +1,54 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: We should return the index of `x` in `seq`.
+Assistant: Good. Now, looking at your code, does it ever return an index `i` such that the element at that index is equal to `x`?
+	<alt>Good. How do you find the index of `x` in a list `seq`?
+	<alt>Good. If the current index is `i`, how do you determine if the element at position `i` in the list `seq` is equal to `x`?
+User: Oh, it always returns a position where `seq[i] > x`. I think I need to also test for equality, let me do that... It works now, thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+</dialogue>

data/raw/v1_bea/evaluation_dataset/15_44_sequential_search_conversational_thread_3.txt

@@ -0,0 +1,55 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: Because the element at position 1 is equal to 5, and according to the problem description whenever the number is present in the input list we should return its position.
+Assistant: Good. Now, can you tell me what happens in your code for test example 1 when `i` takes the value 1? Start with line 3.
+	<alt>Good. Does your code ever test if the number `x` is present in the list?
+	<alt>Good. How can you determine, using code in Python, if a number `x` is present in a list `seq`?
+User: When `i` is 1, `seq[1]` is equal to 5. On line 3, since 5 is not less than 5, this means that line 4 is not executed, so we go back to line `2` where `i` is assigned the next value of 2. Ah, now I understand where the problem is,  I should have tested for equality too, let me do that ... It works now! Thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You are welcome!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/15_44_sequential_search_socratic_dialogue.txt

@@ -0,0 +1,54 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, can you explain why the correct returned value should be 1?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through `if` on line 3?
+User: The correct answer is 1 because 5 is found at position 1 in the input list.
+Assistant: Good. So the input element `x = 5` is present at some position `i = 1` in the list `seq`. Does your code check for this?
+	<alt>Good. What does your code do when position `i = 1`?
+User: Ah, I see now. I should also check if `seq[i]` is equal to `x`. Let me do that... It works now, thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, glad I could help.
+</dialogue>

data/raw/v1_bea/evaluation_dataset/15_45_sequential_search_conversational_thead_1.txt

@@ -0,0 +1,61 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: Can you walk me through how your function handles some simple examples? For example, `search(5, [-1, 5, 8, 10, 12])`.
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: For that example, I get an output of 1. I first iterate through the elements in the list and check when the 5 is less than or equal to the current element, which happens at index 1. 
+	<alt>This just gives an output of 1
+Assistant: I see. What happens when you have a larger `x` value? Try `search(20, [-1, 5, 8, 10, 12])`.
+	<alt>I see. What about when your `x` is not less than or equal to any elements?
+	<alt>That seems right. How do you deal with negative numbers and numbers greater than all the list elements?
+	<alt>Good. Is there a case where your function might not return anything?
+User: For that, my code seems to return `None`. I use the same procedure and iterate through the list element. Oh, I see. Since 20 is greater than all the current list elements, I never get to the `return`
+Assistant: It looks like you just need to handle that other case then. What's a good answer to return when `x` is greater than all the existing elements?
+	<alt>Where would you want to insert an element that is larger than all the current ones?
+	<alt>What's a good place to insert 20 in the example I gave you?
+User: I think I should put it at the end of the list. I'll update the code and see if it works.
+<code>
+ def search(x, seq):
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Looks like it works! Let me know if you need more help
+</dialogue>

data/raw/v1_bea/evaluation_dataset/15_45_sequential_search_socratic_dialogue.txt

@@ -0,0 +1,61 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: What inputs have you tried? When do you get `None`?
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.
+	<alt>I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list
+	<alt>It seems like I get the wrong answer when `x` is bigger than all the existing list elements
+Assistant: Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?
+	<alt>Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?
+	<alt>What do you expect your code to return when `x` is bigger than the `seq` elements?
+User: Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.
+Assistant: What happens if `x` is not less than or equal to any element?
+	<alt>What does your code do if `x` is greater than all of the elements in `seq`?
+User: I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!
+<code>
+ def search(x, seq):    
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Good work. Let me know if you have any other questions.
+User: Thanks!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/16_46_substring_length_conversational_thread_1.txt

@@ -0,0 +1,108 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+	<alt>That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+User: OK. I think I need to look at the substring that starts at the last value of `start` and ends at the end of the string. Let me do that... It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+	<alt>Not sure how to do that, can you help?
+Assistant: That's great! Glad I could help.
+</dialogue>

data/raw/v1_bea/evaluation_dataset/16_46_substring_length_conversational_thread_2.txt

@@ -0,0 +1,110 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+	<alt>That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+User: I think it is the variable `start`, right before `pos` becomes -1. It should end where `s` ends.
+	<alt>I don't know, how can I find that?
+Assistant: Great. Now that you know where it starts and where it ends, can you add code that extracts this substring and looks at its length too?
+User: I did that, and it works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.
+18.    return max_len
+
+</code>
+Assistant: You're welcome, happy to help!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/16_46_substring_length_conversational_thread_3.txt

@@ -0,0 +1,117 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+	<alt>That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+User: I don't know, how can I find that?
+	<alt>I think it is the variable `start`, right before `pos` becomes -1. It should end where `s` ends.
+Assistant: If you look at the test example, 'dabra' appears right after the last occurrence of `ca`. Which variable in your code computes that position?
+	<alt>Can you tell me what the variable `start` is supposed to do and how it is computed?
+	<alt>Which variable in your code computes the index right after the last occurrence of the string `t`?
+User: So it must be the sum between where `ca` starts, which is in `pos` and the length of `ca`, that is what `start` does.
+Assistant: Correct. Now, where does 'dabra' end?
+	<alt>Correct. Can you now write code to extract the string 'dabra' and consider it when computing the maximum length?
+User: It ends at the end of the input string `s`.
+Assistant: Correct. So it starts at the last value of `start` and ends at `len(s)`. Can you now write code to extract the string 'dabra' and consider it when computing the maximum length?
+User: Ok, I did that and it works now. Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.
+18.    return max_len
+
+</code>
+Assistant: Great, glad that I could be of help!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/16_46_substring_length_socratic_dialogue.txt

@@ -0,0 +1,87 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: `max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.
+Assistant: Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?
+	<alt>Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?
+	<alt>Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?
+	<alt>Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?
+User: Ah, I see now. The maximum substring should be "dabra", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.       max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/16_56_substring_length_conversational_thread_1.txt

@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+	<alt>OK. Does `start` ever change inside the while loop?
+User: Ah, I see the problem, I forgot to change `start` inside the while loop. Let me do that ... it works now. Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: Great, happy to help!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/16_56_substring_length_conversational_thread_2.txt

@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. Does `start` ever change inside the while loop?
+User: First, `start` is initialized with 0. Then `pos` becomes 4, then ... ah, I forgot to update `start` inside the loop. Let me try to fix that ... it works! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You are welcome!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/16_56_substring_length_conversational_thread_3.txt

@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. Does `start` ever change inside the while loop?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+User: Ah, it doesn't! It stays equal to 0, which means that `pos` does not change either. Let me fix that... it works! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You are welcome!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/16_56_substring_length_socratic_dialogue.txt

@@ -0,0 +1,72 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Can you tell me the role of the variable `start`?
+User: In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You're welcome!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/17_47_topk_socratic_dialogue.txt

@@ -0,0 +1,95 @@
+<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi. I am confused. My code doesn’t seem to work. Can you help?
+Assistant: Hello. Sure, let's see. Do you know what might be the issue?
+User: I think the problem is with the `.pop()` method. It seems to have issues with indexing.
+	<alt>When I use the `.pop()` method, I get an IndexError on some inputs.
+	<alt>For some inputs, I get an error and other inputs don't produce the right answer.
+Assistant: Ok, no worries. Let's review your code line by line. Could you please explain it to me?
+	<alt>Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?
+	<alt>Let's start with a warm-up question. What does the `.pop()` method do?
+	<alt>Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+	<alt>Could you please explain what line 5 in your code does?
+	<alt>Let’s look into the Python documentation. Can you describe what the `.pop()` method does?
+User: Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.
+Assistant: Good. What can you do right now to debug your code and diagnose what might be causing the problem?
+User: Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.
+	<alt>I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0, 1]`, It seems to work, but when using `[1]`, it throws an error. I think it is removing elements by index and not by value, maybe I should use a different deletion method.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(max(lst))
+6.        lst.pop(max(lst))
+7.        print(lst)
+8.    return result
+
+</code>
+Assistant: Are there other ways of debugging the `.pop()` method?
+	<alt>What happens if you use a different input value for the `top_k()` function?
+	<alt>Have you considered using the debugger?
+	<alt>What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+User: Hm... I probably could use a different value as the input for this method. So using 1 as the input value worked. The `.pop()` method seems to remove the value that has the index value of 1 in the given list. This is not what I was expecting from this method. What should I do?
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(lst)
+6.        lst.pop(1)
+7.        print(lst)
+8.    return result 
+
+</code>
+Assistant: Perhaps there are other solutions you can use aside from `.pop()`?
+	<alt>Where can we learn more about other list methods that can help us remove elements from an array?
+	<alt>I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: I think but I can't remember them...
+Assistant: I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: Ok. Oh I see, I used the wrong method. I should use `.remove()` instead. Aha! It works now. I removed the print statements also.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.remove(max(lst))
+6.    return result
+
+</code>
+Assistant: Great! Please let me know if you need help with anything else.
+</dialogue>

data/raw/v1_bea/evaluation_dataset/17_47_topk_socratic_thread_1.txt

@@ -0,0 +1,76 @@
+<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi. I am confused. My code doesn’t seem to work. Can you help?
+Assistant: Hello. Sure, let's see. Do you know what might be the issue?
+User: I think the problem is with the `.pop()` method. It seems to have issues with indexing.
+	<alt>When I use the `.pop()` method, I get an IndexError on some inputs.
+	<alt>For some inputs, I get an error and other inputs don't produce the right answer.
+Assistant: Ok, no worries. Let's review your code line by line. Could you please explain it to me?
+	<alt>Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?
+	<alt>Let's start with a warm-up question. What does the `.pop()` method do?
+	<alt>Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+	<alt>Could you please explain what line 5 in your code does?
+	<alt>Let’s look into the Python documentation. Can you describe what the `.pop()` method does?
+User: Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.
+Assistant: Good. What can you do right now to debug your code and diagnose what might be causing the problem?
+User: I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0,1]`, It seems to work, but `[1]`, it throws an error. 
+	<alt>Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(max(lst))
+6.        lst.pop(max(lst))
+7.        print(lst)
+8.    return result 
+
+</code>
+Assistant: What does that tell you about the `.pop()` method?
+	<alt>What conclusion can you draw from examining the output of the `.pop()` method?
+User: I think it is removing by index and not value, maybe I should use a different deletion method. I'll try `.remove()`. It works!
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.remove(max(lst))
+6.    return result
+
+</code>
+Assistant: Great! Glad to help
+</dialogue>

data/raw/v1_bea/evaluation_dataset/18_48_password_validator_conversational_thread_1.txt

@@ -0,0 +1,89 @@
+<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string "Welcome!" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns "I don't know you.". If menu_choice is 'a', the function adds the password to the dictionary and returns "Password added!". If the password is already in the dictionary, the function returns "Password already exists!".
+## Example Cases:
+```
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+validate_or_add_password("v", "abc123", passwords_dict) => "Welcome!"
+validate_or_add_password("v", "xyz789", passwords_dict) => "I don't know you."
+validate_or_add_password("a", "abc123", passwords_dict) => "Password already exists!"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password added!"
+passwords_dict[4] => "newpass"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password already exists!"
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            return "Password added!"
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+assert validate_or_add_password("v", "abc123", passwords_dict) == "Welcome!"
+assert validate_or_add_password("v", "xyz789", passwords_dict) == "I don't know you."
+assert validate_or_add_password("a", "abc123", passwords_dict) == "Password already exists!"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password added!"
+assert passwords_dict[4] == "newpass"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password already exists!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I need help with this code. It's throwing a `KeyError`. I'm not sure why.
+	<alt>Hello. I need help with my code.
+Assistant: Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+	<alt>Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>What does `KeyError` typically mean and why does it occur?
+	<alt>Let's look at the example cases, where do you see `4` being used as a key?
+	<alt>Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+	<alt>Which parameter in the `validate_or_add_password` function is a data structure that uses keys?
+	<alt>Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+User: After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist. I wonder if this relates to adding a new password.
+Assistant: Good hypothesis. Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+	<alt>Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?
+	<alt>Good. Which test case do you think is causing the `KeyError`?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+User: Certainly. So when `menu_choice` is `"a"` we go to line 8, we check if  `password` is already stored in `passwords_dict`. If so, the function returns "Password already exists!" otherwise it returns "Password added!".
+Assistant: Good. Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+	<alt>According to the problem description, what do you need to do with `password` if `menu_choice` is `"a"`?
+User: Oh. It is supposed to add `password` to `passwords_dict` and then return "Password added!". Let me edit my code.
+<code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            passwords_dict[len(passwords_dict) + 1] = password
+12.            return "Password added!"
+
+</code>
+Assistant: Good. Have you tried your code on all the example cases?
+User: Yes. It works correctly! Thank you for helping me today!
+Assistant: You're welcome. Let me know if I can be of any further assistance in the future.
+</dialogue>

data/raw/v1_bea/evaluation_dataset/18_48_password_validator_socratic_dialogue.txt

@@ -0,0 +1,90 @@
+<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string "Welcome!" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns "I don't know you.". If menu_choice is 'a', the function adds the password to the dictionary and returns "Password added!". If the password is already in the dictionary, the function returns "Password already exists!".
+## Example Cases:
+```
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+validate_or_add_password("v", "abc123", passwords_dict) => "Welcome!"
+validate_or_add_password("v", "xyz789", passwords_dict) => "I don't know you."
+validate_or_add_password("a", "abc123", passwords_dict) => "Password already exists!"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password added!"
+passwords_dict[4] => "newpass"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password already exists!"
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            return "Password added!"
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+assert validate_or_add_password("v", "abc123", passwords_dict) == "Welcome!"
+assert validate_or_add_password("v", "xyz789", passwords_dict) == "I don't know you."
+assert validate_or_add_password("a", "abc123", passwords_dict) == "Password already exists!"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password added!"
+assert passwords_dict[4] == "newpass"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password already exists!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello. I need help with my code.
+	<alt>I need help with this code. It's throwing a `KeyError`. I'm not sure why.
+Assistant: Can you describe the issue you are experiencing?
+	<alt>Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+	<alt>Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+User: I am getting a `KeyError: 4`. Not really sure why.
+	<alt>My terminal is printing `KeyError: 4`. I think it's failing a test case perhaps.
+Assistant: Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>What does `KeyError` typically mean and why does it occur?
+	<alt>Let's look at the example cases, where do you see `4` being used as a key?
+	<alt>Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+	<alt>Which parameter in the `validate_or_add_password` function is a data structure that uses keys?
+User: After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist.
+Assistant: Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?
+	<alt>Good. Which test case do you think is causing the `KeyError`?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+User: Ah found it. In the example cases, line 18 is trying to access the value using the key 4 `passwords_dict[4] == "newpass"`. However, `passwords_dict` is initialized to `passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}` and does not have 4 as a key.
+	<alt>Ah found it. In the example cases, this line is trying to access the value using the key 4 `passwords_dict[4] == "newpass"` after calling `validate_or_add_password("a", "newpass", passwords_dict)` in an attempt to add "newpass" as a password.
+Assistant: Good. What is the statement right before line 18 attempting to do?
+User: Oh! I get it now! This example case is testing whether my function adds `"newpass"` to `passwords_dict`. I don't think I do that. I thought I just need to print "Password added!". Let me edit my code to ensure that it adds `password` to `passwords_dict` in this case.
+<code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            passwords_dict[len(passwords_dict) + 1] = password
+12.            return "Password added!"
+
+</code>
+Assistant: Good. Does your code pass all the example cases?
+User: Yes it does thank you for your help. I learned more about `KeyError`s today.
+Assistant: You're welcome to let me know if I can be of any further assistance.
+</dialogue>

data/raw/v1_bea/evaluation_dataset/1_10_calculating_a_grade_conversational_thread_1.txt

@@ -0,0 +1,132 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: Can you explain the differences between `finalScore` and `roundedScore`?
+User: `finalScore` is the unrounded grade and `roundedScore` is the rounded version.
+	<alt>Oh! I see now, I put the wrong score into the comparisons. It works now, thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: And which of those values are you returning with the letter grade?
+User: Oh! I'm returning a letter calculated from `finalScore` and the grade from `roundedScore`. I fixed the issue, thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+</dialogue>

data/raw/v1_bea/evaluation_dataset/1_10_calculating_a_grade_conversational_thread_2.txt

@@ -0,0 +1,111 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to finalScore is 69.6.
+	<alt>The value would be 70, right?
+Assistant: What is the truth value of the boolean expression on line 14?
+	<alt>Correct. Which block of the if-elif-else statement is executed?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+User: It would be false, it wouldn't produce the right `letterGrade`.
+	<alt>It would be true, 70=70.
+Assistant: Correct. But you said you were still returning 70, why do you think that is?
+User: Oh! I'm returning `roundedScore`! If I compare by that too, then I get consistent results. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+</dialogue>

data/raw/v1_bea/evaluation_dataset/1_10_calculating_a_grade_conversational_thread_3.txt

@@ -0,0 +1,162 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+User: I am returning ('D', 70) for test 4 and I don't know why.
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: What is the truth value of the boolean expression on line 14?
+User:  It would be true, 70=70.
+Assistant: Is that true? Can you verify that?
+	<alt>What does the boolean expression on line 14 evaluate to?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+	<alt>Is that true? Can you print the value of `finalScore >= 70`?
+	<alt>Correct. Which block of the if-elif-else statement is executed?
+User: Yes, I'll use a print statement to do that.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.    
+10.    print(finalScore >= 70)
+11.
+12.    if finalScore >= 90:
+13.        letterGrade = "A"
+14.    elif finalScore >= 80:
+15.        letterGrade = "B"
+16.    elif finalScore >= 70:
+17.        letterGrade = "C"
+18.    elif finalScore >= 60:
+19.        letterGrade = "D"
+20.    else:
+21.        letterGrade = "F"
+22.    return letterGrade, roundedScore
+
+</code>
+Assistant: And what does it print for test 4?
+User: It prints `False` but I don't know why.
+	<alt>Oh, it prints `False` because it's 69.6, not 70. I need to use `roundedScore` instead. That makes it work, thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: And what is the value of `finalScore` when you use it on line 10?
+	<alt>How does the value of `finalScore` affect the truth value of the boolean expression on line 10?
+User: Oh! I was using the wrong variable. After switching `finalScore` to `roundedScore` in the comparisons it worked. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+</dialogue>

data/raw/v1_bea/evaluation_dataset/1_10_calculating_a_grade_socratic_dialogue.txt

@@ -0,0 +1,138 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: Correct. Which block of the if-elif-else statement is executed?
+	<alt>What does the boolean expression on line 14 evaluate to?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+	<alt>What is the truth value of the boolean expression on line 14?
+User: Oh! The boolean on line 16 becomes true, assigning `letterGrade` to 'D'! But I'm not sure how to fix that.
+	<alt>Oh, I put `finalScore` instead of `roundedScore`!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: How would you ensure that the grade would be treated as its nearest integer for the comparison?
+	<alt>How does your code return a grade of 70, yet compares with 69.6?
+User: Oh! I used the wrong variable. After using `roundedScore` that fixed it. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good. Happy to help. Let me know if you have any further questions!
+User: Thank you so much for your help again!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/1_11_calculating_a_grade_conversational_thread_1.txt

@@ -0,0 +1,88 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+    <alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Let's look at the instructions. Is there any information that is missing or not being displayed in your output?
+	<alt>What seems to be missing from your output if you run your code and compare it with the expected output?
+User: I want to return two variables `letterGrade` and `roundedScore` but my function only returns `letterGrade`.
+	<alt>I want to return two variables, but my code only returns one even though I am trying to return both.
+	<alt>I am attempting to return two variables in my code, but only one is being returned despite my efforts to return both.
+Assistant: At which line are you attempting to return two variables?
+User: Although I am returning `letterGrade` on line 14 and `roundedScore` on line 15, it seems like line 15 never runs.
+	<alt>I am returning the variables on lines 14 and 15, but it seems like the code stops after line 14.
+Assistant: Based on the observed behavior, do you believe a function can contain two back-to-back return statements?
+	<alt>After looking at the comparison with the instructions, do you think this might be the correct way to return multiple variables?
+User: No, I think I can only use one return statement. But how do I return multiple variables?
+	<alt>How do I return multiple variables with only one return statement?
+Assistant: Let's refer back to the instructions, and this time we will pay attention to the data type of the expected output. What do you observe?
+User: The expected output consists of a tuple. I suppose I can return the variables together as a tuple with one return statement. I'll try that now.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.   elif roundedScore >= 60:
+11.       letterGrade = "D"
+12.   else:
+13.       letterGrade = "F"
+14.   return (letterGrade, roundedScore)
+
+</code>
+Assistant: Does your output match the expected output now?
+User: It displays the expected output.
+</dialogue>

data/raw/v1_bea/evaluation_dataset/1_11_calculating_a_grade_socratic_dialogue.txt

@@ -0,0 +1,96 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+	<alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: The function only seems to return the `letterGrade` but otherwise it runs alright.
+	<alt>It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Python code runs line-by-line. Let's look at yours again - can you pinpoint where the problem might be?
+User: Yes, it seems like line 15 never runs. Does that mean my function stops at line 14?
+	<alt>It seems like the last line never executes.
+Assistant: Good! Given this observation, when does your function terminate?
+	<alt>Good! Can you describe what are you trying to do on line 15?
+	<alt>What makes you think line 15 is not being executed?
+	<alt>Can you describe what are you trying to do on lines 14 and 15?
+User: It seems like once the return statement has executed, the function does not go further.
+Assistant: Is it possible for a function to have two consecutive return statements? 
+	<alt>Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+	<alt>How about we look up this behavior in the documentation to get more clarity?
+User: It seems like I can only use one return statement here. What should I do to return both `letterGrade` and `roundedScore`?
+	<alt>But then how do I make sure to return both the `letterGrade` and `roundedScore`?
+	<alt>Looking at the documentation, it seems I can only use one return statement per function. However, I would still have a problem with returning both the `letterGrade` and `roundedScore`!
+Assistant: Good question! Let's turn to the documentation - how can we return multiple variables?
+	<alt>Let's look at the instructions. When looking at the function signature, can you determine the data type that is specified as the return value?
+	<alt>Let's look at the examples in the instructions. What do you notice is being returned?
+User: Ah I see. Looks like I need only one statement, but I can include more variables in the same statement. Updating my code now.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.   elif roundedScore >= 60:
+11.       letterGrade = "D"
+12.   else:
+13.       letterGrade = "F"
+14.   return letterGrade, roundedScore
+
+
+</code>
+Assistant: Great job! Is your code working now?
+	<alt>Did that fix your problem?
+User: Yes it did, thanks!
+	<alt>I'm all done!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/1_13_calculating_a_grade_socratic_dialogue.txt

@@ -0,0 +1,183 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.1, 0.3, 0.4, 0.2]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+</bug_code>
+<bug_desc>
+On lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.
+</bug_desc>
+<bug_fixes>
+On line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.
+On line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck
+Assistant: Okay, what do you think the problem is?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Have you thought about the problem?
+User: It isn't calculating correctly.
+	<alt>It's failing the second test case.
+Assistant: How is the calculation made in the function?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Where do you think the problem is?
+	<alt>Start with line 1, do you see any problems with the method header?
+	<alt>Look at the second test case, how is it different from the first test case?
+User: The scores are multiplied with the weights and summed up.
+	<alt>Pass in the scores, put them in an array, multiply those values with the weights, and add them with a for-loop.
+Assistant: So, is it working for the first test case?
+	<alt>Do you see any problems adding the scores on the assignments to the grades array?
+	<alt>Do you see any problems with the loop?
+	<alt>Do you see any problems with the weights?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt> Why is it working on the first test case and not the second?
+	<alt> Check the loop, are all the values being considered?
+User: Yes, the first test case is correct, but the second one is wrong.
+Assistant: How are the two test cases different?
+	<alt>Do you see any problems with the weights?
+	<alt>Do you see any problems with passing in the grades?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt>Do you see any differences in the numbers between the two test cases?
+User: The first test case has all the values the same, and the second test case has different values.
+	<alt>The first test case has all 100s, but different numbers for the second case.
+	<alt>I'm not sure.
+Assistant: Does the order of the input parameters matter?
+	<alt>Why does the order matter?
+	<alt>Are any specific lines of code impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Which parameter represents homework?
+User: Yes, the order of inputs does matter.
+Assistant: Why?
+	<alt>Which lines are impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Look back at the instructions, what should the weight be for the first value?
+User: Because that determines which value is associated with the different grade categories.
+Assistant: Why does that change the calculation?
+	<alt>What is the correct weight for the homework?
+	<alt>On what line of code are those values assigned?
+	<alt>Are those values passed into the array in the proper order?
+User: The type of grade changes the weight for the calculation.
+Assistant: What is the correct weight for homework?
+	<alt>Look at the grades array, does it match the order the parameters are passed in?
+	<alt>Look at the weights array, does that match the order for the categories?
+	<alt>What do you think is causing the problem here?
+User: Homework should have a weight of 20%.
+Assistant: How is that set in the code?
+	<alt>What weight should exams have?
+	<alt>Look at the weights array, does that match the order for the categories?
+User: It's set in the weights array.
+	<alt>I see, the weights array is wrong!
+Assistant: Check the weights array, does the first item match the correct weight for homework?
+	<alt>How does the weights array interact with the grades array?
+	<alt>Which item in the weights array should correspond with homework?
+	<alt>Are the arrays parallel?
+User: No, the first item is 0.1, that's the weight for attendance.
+	<alt>It's in the wrong order.
+Assistant: What should you change the weights array to?
+	<alt>Should the first item in the weights array go with the first item in the grades array?
+	<alt>Should the arrays be parallel?
+	<alt>Are the arrays parallel?
+User: I'll switch the attendance and homework weights on line 2.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.3, 0.4, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Did that fix it?
+	<alt>Is that everything?
+	<alt>Did you check the other weights?
+User: No, it still doesn't work.
+Assistant: Keep looking, do you see any other problems with the weights array?
+	<alt>Did which test cases pass change?
+	<alt>Does the first test case still pass?
+	<alt>What about the second item in the grades array, does it match with the second item in the weights array?
+	<alt>What is the correct weight for exams?
+User: Yes, exams and projects are flipped too!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.4, 0.3, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Does it pass now?
+User: Yes, all the test cases pass. Thank you!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/1_8_calculating_a_grade_socratic_dialogue.txt

@@ -0,0 +1,179 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore > 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.    elif roundedScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+When `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `roundedScore > 90` with `roundedScore >= 90` on line 4.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>What test cases are passing?
+	<alt>What test cases are failing?
+	<alt>Have you reread the prompt?
+	<alt>Have you checked the calculation for the grade?
+	<alt>Have you checked the if-statement?
+User: I don't know.
+Assistant: Let's go through your function line by line, how can you check the calculation on line 2?
+	<alt>Let's start by looking at the test cases, what is the first one to fail?
+	<alt>Let's start by looking at the test cases, does the first one pass?
+User: I can add a print statement to check the number.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    if roundedScore > 90:
+6.        letterGrade = "A"
+7.    elif roundedScore >= 80:
+8.        letterGrade = "B"
+9.    elif roundedScore >= 70:
+10.        letterGrade = "C"
+11.    elif roundedScore >= 60:
+12.        letterGrade = "D"
+13.    else:
+14.        letterGrade = "F"
+15.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good, what is the first test case to fail?
+	<alt>Good, does the first test case succeed?
+	<alt>Good, is the first `finalScore` correct?
+	<alt>Good, what is the first incorrect `finalScore`?
+User: The second test case fails.
+Assistant: Is the `finalScore` correct for that test case?
+	<alt>Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+	<alt>How can you check if it is a rounding error?
+User: Yes, the final score is correct for that test case.
+Assistant: How can you check if it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+User: I can add another print statement after line 4 and check the rounding.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore > 90:
+7.        letterGrade = "A"
+8.    elif roundedScore >= 80:
+9.        letterGrade = "B"
+10.    elif roundedScore >= 70:
+11.        letterGrade = "C"
+12.    elif roundedScore >= 60:
+13.        letterGrade = "D"
+14.    else:
+15.        letterGrade = "F"
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good. Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: No, I don't think so.
+Assistant: Now, let's look at the if-statement that matches letters to the grades. Can you tell me what the first statement checks?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: It checks if the rounded score is greater than 90.
+	<alt>I see, it should be greater than or equal to!
+Assistant: Think about that carefully, would it return true or false if the grade was exactly 90?
+User: No, it wouldn't! That's wrong, it should be greater than or equal to!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore >= 90:
+7.        letterGrade = "A"
+8.    elif roundedScore >= 80:
+9.        letterGrade = "B"
+10.    elif roundedScore >= 70:
+11.        letterGrade = "C"
+12.    elif roundedScore >= 60:
+13.        letterGrade = "D"
+14.    else:
+15.        letterGrade = "F"
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Try running it again, does it work now?
+User: Yes! It does. I'll remove the extra print statements.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.    elif roundedScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good.
+User: Thank you!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/22_53_cookie_purchase_conversational_thread_1.txt

@@ -0,0 +1,75 @@
+<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {"discount": discount, "price": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm having a problem with my code
+	<alt>Hi! My code seems to sometimes give answers that are very off
+Assistant: What seems to be the issue?
+	<alt>Can you walk me through your function line by line?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is divisible by 10?
+User: My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code
+Assistant: Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?
+	<alt>Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?
+	<alt>Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?
+	<alt>Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?
+User: I think there should be a discount of 10% but when I run `cookiePurchase(70)`, I get a discount of 0. I'm so lost.
+Assistant: Let's review the problem description again. What are the conditions for a discount and where in your code do you check for these conditions?
+	<alt>From the task description, you need to check whether the number of cookies is divisible by 10, and it looks like you fail on an input that is divisible by 10. Can you explain how you're checking whether 70 is divisible by 10?
+User: The task description tells me to check whether the number of `cookies` is greater than 10 and whether `cookies` is a multiple of 10, and I fail on 70 cookies, so maybe I'm not checking this properly.
+Assistant: Let's walk through your if statement on line 4 then. 70 > 10 is True, but what is the value of `cookies / 10` when `cookies` is 70?
+User: So, for 70, I first check if it is greater than 10, which it is, and then I check whether it is a multiple of 10. I do this by dividing by 10 and seeing if the output is 0. Wait, that's not right. 70 / 10 is 7, not 0.
+	<alt>So, for 70, I first check that it is greater than 10, and then I divide by 10 to check divisibility
+Assistant: Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?
+	<alt>What operator should you use to check whether a number is a multiple of 10?
+	<alt>Where can you learn more about Python operators?
+User: Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...
+Assistant: Where can you learn more about arithmetic operators in Python?
+	<alt>Let's take a look at the Python documentation to see if there is a different operator that does what you want.	
+User: Ah! The Python documentation would be good to look at right now. Looking at the documentation, I think I should be using the modulus operator. I'll try that.
+<code>
+ def cookiePurchase(cookies):
+    price = cookies * 1.75
+    discount = 0
+    if cookies > 10 and cookies % 10 == 0:
+        discount = price * 0.1
+        price = price - discount
+    return {"discount": discount, "price": price}
+
+</code>
+Assistant: Looks like it works!
+User: Yes it does for all the test cases! Thank you so much!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/22_53_cookie_purchase_socratic_dialogue.txt

@@ -0,0 +1,69 @@
+<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {"discount": discount, "price": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm having a problem with my code
+	<alt>Hi! My code seems to sometimes give answers that are very off.
+Assistant: What seems to be the issue?
+	<alt>Can you walk me through your function line by line?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is divisible by 10?
+User: My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code.
+Assistant: Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?
+	<alt>Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?
+	<alt>Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?
+	<alt>Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?
+User: First, I calculate the price based on the number of cookies. Then, I check whether I should apply a discount by checking the number of cookies and dividing by 10 to determine whether that number is a multiple of 10. Then I apply the discount if it is relevant. So for 70 cookies, I would calculate the price to be 70 * 1.75 = 122.5. Then I would check whether 70 > 10 which is True but 70 / 10 == 0, is false, so I would not apply a discount and would return the full price of 122.5. That's incorrect.
+Assistant: Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?
+	<alt>What operator should you use to check whether a number is a multiple of 10?
+	<alt>Where can you learn more about Python operators?	
+User: Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...
+Assistant: Let's take a look at the Python documentation to see if there is a different operator that does what you want.
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Oh, interesting. The modulus operator seems to fit. I'll modify my code and see if it works. It looks like it does!
+<code>
+ def cookiePurchase(cookies):
+    price = cookies * 1.75
+    discount = 0
+    if cookies > 10 and cookies % 10 == 0:
+        discount = price * 0.1
+        price = price - discount
+    return {"discount": discount, "price": price}
+
+</code>
+Assistant: Great! Glad to help.
+User: Thank you very much!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/24_29_factorial_conversational_thread_1.txt

@@ -0,0 +1,78 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For `n = 1` or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.
+	<alt>The first value assigned to `i` will be 1.
+	<alt>Oh! `i` is not declared before the for loop is created, maybe that causes this issue.
+Assistant: That’s right. So, what happens when `i` is 0?
+	<alt>Correct. Given that `i` is 0, what happens when line 6 is evaluated?
+User: We go into the for loop and compute `fact`.
+	<alt>The value of `fact` will be 0 because `i` is 0. I think I got it `fact` will always be because of this. I need to change the `range` call to start at 1 instead of 0 and end at `n+1` instead of `n`.
+Assistant: That's right. Given that `i` is 0, what will the value of `fact` be after line 6 is executed?
+User: Aha! I see what is happening. `fact` is always 0 because `i` is 0 in the first iteration of the for loop. I need to change the range to start at 1 instead of 0 and end at `n+1` instead of `n`.  Thanks! I think I got it now.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(1, n + 1):
+6.                fact = fact * i
+7.        return fact
+</code>
+Assistant: I am glad I could help. If you have any other questions, please let me know.
+User: Thank you!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/24_29_factorial_conversational_thread_2.txt

@@ -0,0 +1,82 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For n = 1 or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: Oh! `i` is not declared before the for loop is created, maybe that causes this issue.
+Assistant: Let's examine what happens in this case. Open the Python shell and type `[i for i in range(1)]`. What do you see?
+	<alt>Let's investigate this further. Open the Python shell and type `for i in range(1): print(i)`. Press `Enter` twice to execute. What do you see?
+User: I see that `i` is not declared before the for loop is created. Yet the list comprehension `[i for i in range(1)]` returns `[0]`. So the issue is not with initializing `i` before the for loop.
+	<alt>I see a `[0]` in the list comprehension `[i for i in range(1)]`. So the issue is not with initializing `i` before the for loop but rather with the first value of `i` in the for loop. It is not 1 but 0 so `fact` will always be 0.
+Assistant: Good. Let's take a closer look. What is the first value of `i` in the for loop?
+	<alt>Correct. What do you notice about the first value of `i` in the for loop?
+	<alt>Notice that the value of `i` in the first iteration of the for loop is 0. How do you think this affects the value of `fact`?
+User: I see. The value of `i` in the first iteration of the for loop is 0. So `fact` will always be 0 because the first value of `fact = 1 * 0` is 0. Then, `fact` will be `0 * 1` in the second iteration of the for loop, and so on.
+Assistant: Good! How can we fix this issue?
+	<alt>Good. Now, what does a correct factorial sequence look like for `n=4`?
+User: I think we can fix this by changing the range of `i` to `range(1, n + 1)`.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(1, n + 1):
+6.                fact = fact * i
+7.        return fact
+</code>
+Assistant: Good! Let's test it. What is the factorial of 5?
+User: The factorial of 5 is 120. It works!
+Assistant: I am glad I could help. If you have any other questions, feel free to ask me.
+User: Thank you!
+</dialogue>

data/raw/v1_bea/evaluation_dataset/24_29_factorial_conversational_thread_3.txt

@@ -0,0 +1,166 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of n it fails and what values it returns in those cases?
+User: For n = 1 or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: The first value assigned to `i` will be 1.
+	<alt>Aaah, I understand! The first value assigned to `i` will be 0, because `range` by default starts at 0.
+	<alt>Oh! `i` is not declared before the for loop is created maybe that causes this issue.
+Assistant: Are you sure about that? Can you verify that the first value assigned to `i` is 1?
+User: OK, let me print its value at each iteration. I see, the first value is 0, not 1!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i
+8.        return fact
+
+</code>
+	<alt>OK, let me check in the Python documentation what range does. I see, the first value is 0, not 1!
+Assistant: How can you fix the code so that in the first iteration fact is multiplied with 1, not with 0?
+	<alt>Why do you think the first value is 0?
+User: I don’t know, can you help?
+	<alt>I will multiply fact with `i + 1`. Let me do that … It works! Thank you for your help!
+	<alt>I can change to `range(1,  n + 1)` so that it starts iterating at 1.
+	<alt>I can change to `range(1, n)` so that it starts iterating at 1.
+	<alt>I can change to `range(n) + 1`, so that the first value is 0 + 1.
+Assistant: How can you ensure that in the first iteration `fact` is multiplied with 1?
+User: I can add a line that sets `i` to 1 before the for loop.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(n):
+7.                print(i)
+8.                fact = fact * i
+9.        return fact
+
+</code>
+Assistant: Let’s see if that works. Can you try it for `n = 1`?
+	<alt>Ok! Let's run the code for `n = 2` and see what happens.
+User: Hm... It still returns 0.
+	<alt>It still returns 0. I think I need to change the for loop.
+Assistant: Do you know why it still returns 0?
+	<alt>What do you think `range(n)` is doing to `i`?
+	<alt>Let’s look at the terminal output. What value is `i` on line 7 when being printed?
+User: I think the problem is that `i` is still 0 in the first iteration of the for loop. It still prints 0. I think I can add an `if` statement to the for loop that checks if `i` is 0 and if so, sets it to 1.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(n):
+7.                if i == 0:
+8.                    i = 1
+9.                  print(i)
+10.                fact = fact * i
+11.        return fact
+
+</code>
+	<alt>It still prints 0. I think I need to make a change in the for loop.
+	<alt>I don't know. Can you help?
+Assistant: Let’s see if that works. Can you try it for `n = 1`?
+	<alt>Ok! Let's run the code for `n = 2` and see what happens.
+	<alt>Did you try it for `n >=2`?
+User: It works! Thank you for your help!
+Assistant: Good. Can you try it for `n = 2` and `n = 3`?
+	<alt>Ok! Let's run the code for `n = 3` and see what happens.
+	<alt>Did you try it for `n >=2`?
+User: Hm... it's incorrect for both `n = 2` and `n = 3`. I think I need to multiply `fact` starting from 1, then 2, then 3 instead of what I'm doing now 1, then 1, then 2.
+Assistant: Good. How can you change the for loop so that the iterator variable `i` is not equal to 0 in the first iteration of the for loop?
+	<alt>What do you think `range(n)` is doing to `i`?
+	<alt>How can you edit the code so that `fact` is multiplied with 1, then 2, then 3?
+	<alt>What do you think you can do to make sure that `fact` is multiplied with 1, then 2, then 3?
+	<alt>How can you change the for loop so that the iterator variable `i` iterates starting from 1?
+User: I think I am going to change `range` to `range(1, n + 1)` so that it starts iterating at 1.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(1, n + 1):
+7.                print(i)
+8.                fact = fact * i
+9.        return fact
+
+</code>
+	<alt>I think I am going to change `range` to `range(1, n)` so that it starts iterating at 1.
+	<alt>I think I am going to change `range` to `range(n) + 1` so that the first value is 0 + 1.
+Assistant: Sounds good, let's try it for `n = 2` and `n = 3` again.
+	<alt>Did you try it again for `n >=2`?
+User: It works! Thank you for your help!
+Assistant: Awesome. Don't forget to remove the print statement before you submit your code.
+	<alt>Good! I’m glad I could help. If you have any other questions, feel free to ask me again.
+User: Thank you! I will do that.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(1, n + 1):
+7.                fact = fact * i
+8.        return fact
+</code>
+Assistant: I’m glad I could help. If you have any other questions, feel free to ask me again.
+User: Thank you!
+</dialogue>