| Expression
				 stringlengths 5 66 | Result
				 float64 -99 10k | Steps
				 stringlengths 47 107 | 
|---|---|---|
| 
	areaoftrianglewith  base 31 and  height21 =  325.50 | 325.5 | 
	Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 31 × 21 = 325.50 | 
| 
	perimeterof rectangle withwidth21and  height 44 = 130 | 130 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (21 + 44) = 2 × 65 = 130 | 
| 
	perimeter of rectangle with  width  50andheight8  = 116 | 116 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (50 + 8) = 2 × 58 = 116 | 
| 
	56+ 9 = 65 | 65 | 
	Step 1: Compute 56 + 9.
Step 2: The result is 65. | 
| 
	perimeter ofrectanglewith width 2 andheight50  =104 | 104 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (2 + 50) = 2 × 52 = 104 | 
| 
	hypotenuse of right  triangle  with  legs  30  and 24  = 38.42 | 38.42 | 
	Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(30² + 24²) = sqrt(900 + 576) = sqrt(1476) = 38.42 | 
| 
	hypotenuse  of right  triangle with legs 1and 25  = 25.02 | 25.02 | 
	Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(1² + 25²) = sqrt(1 + 625) = sqrt(626) = 25.02 | 
| 
	20  /  10 =2 | 2 | 
	Step 1: Compute 20 / 10.
Step 2: The result is 2. | 
| 
	22 /11=2 | 2 | 
	Step 1: Compute 22 / 11.
Step 2: The result is 2. | 
| 
	hypotenuse  of righttriangle  withlegs  23and 17 =28.60 | 28.6 | 
	Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(23² + 17²) = sqrt(529 + 289) = sqrt(818) = 28.60 | 
| 
	area of  rectanglewithwidth 25 and  height  40=1000 | 1,000 | 
	Step 1: Area formula is width × height.
Step 2: 25 × 40 = 1000 | 
| 
	perimeter oftriangle  with  sides8,  31, 12=51 | 51 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 8 + 31 + 12 = 51 | 
| 
	73+ 44 = 117 | 117 | 
	Step 1: Compute 73 + 44.
Step 2: The result is 117. | 
| 
	area  of circle  withradius 10=  314.16 | 314.16 | 
	Step 1: Area formula is π × r².
Step 2: π × 10² = 3.14 × 100 = 314.16 | 
| 
	perimeter of  rectangle  with  width 14and height  2 =32 | 32 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (14 + 2) = 2 × 16 = 32 | 
| 
	2  ** 2= 4 | 4 | 
	Step 1: Compute 2 ** 2.
Step 2: The result is 4. | 
| 
	perimeterofcirclewithradius17= 106.81 | 106.81 | 
	Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 17 = 106.81 | 
| 
	area  ofrectangle  withwidth1 andheight  8 =8 | 8 | 
	Step 1: Area formula is width × height.
Step 2: 1 × 8 = 8 | 
| 
	23 -  46  =-23 | -23 | 
	Step 1: Compute 23 - 46.
Step 2: The result is -23. | 
| 
	area of rectangle  withwidth 30 and height24 = 720 | 720 | 
	Step 1: Area formula is width × height.
Step 2: 30 × 24 = 720 | 
| 
	perimeter of circle with  radius 19 =119.38 | 119.38 | 
	Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 19 = 119.38 | 
| 
	area of rectangle with width 10 and  height3=30 | 30 | 
	Step 1: Area formula is width × height.
Step 2: 10 × 3 = 30 | 
| 
	perimeterof  rectangle  with  width 37and  height8=  90 | 90 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (37 + 8) = 2 × 45 = 90 | 
| 
	85 %8=5 | 5 | 
	Step 1: Compute 85 % 8.
Step 2: The result is 5. | 
| 
	58  *  22  =1276 | 1,276 | 
	Step 1: Compute 58 * 22.
Step 2: The result is 1276. | 
| 
	10  /(10)=1 | 1 | 
	Step 1: Compute 10 / 10.
Step 2: The result is 1. | 
| 
	34 + 13=47 | 47 | 
	Step 1: Compute 34 + 13.
Step 2: The result is 47. | 
| 
	(7) **(3) =  343 | 343 | 
	Step 1: Compute 7 ** 3.
Step 2: The result is 343. | 
| 
	3  ** 3  =  27 | 27 | 
	Step 1: Compute 3 ** 3.
Step 2: The result is 27. | 
| 
	(60) /10 =  6 | 6 | 
	Step 1: Compute 60 / 10.
Step 2: The result is 6. | 
| 
	perimeter of triangle  withsides 47,22,  40  =  109 | 109 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 47 + 22 + 40 = 109 | 
| 
	(69)  - 47  =22 | 22 | 
	Step 1: Compute 69 - 47.
Step 2: The result is 22. | 
| 
	(71) - 49 =  22 | 22 | 
	Step 1: Compute 71 - 49.
Step 2: The result is 22. | 
| 
	area  of trianglewithbase21 andheight  28 = 294.00 | 294 | 
	Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 21 × 28 = 294.00 | 
| 
	54%20  = 14 | 14 | 
	Step 1: Compute 54 % 20.
Step 2: The result is 14. | 
| 
	24  -48  = -24 | -24 | 
	Step 1: Compute 24 - 48.
Step 2: The result is -24. | 
| 
	8 **3=512 | 512 | 
	Step 1: Compute 8 ** 3.
Step 2: The result is 512. | 
| 
	52 %13  =  0 | 0 | 
	Step 1: Compute 52 % 13.
Step 2: The result is 0. | 
| 
	area of rectangle with width14and  height 33  =  462 | 462 | 
	Step 1: Area formula is width × height.
Step 2: 14 × 33 = 462 | 
| 
	hypotenuseof  righttrianglewithlegs13 and 9= 15.81 | 15.81 | 
	Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(13² + 9²) = sqrt(169 + 81) = sqrt(250) = 15.81 | 
| 
	perimeter ofrectanglewithwidth 37  and height  50 = 174 | 174 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (37 + 50) = 2 × 87 = 174 | 
| 
	area  oftrianglewithbase44  and  height36  = 792.00 | 792 | 
	Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 44 × 36 = 792.00 | 
| 
	5  **2  =  25 | 25 | 
	Step 1: Compute 5 ** 2.
Step 2: The result is 25. | 
| 
	perimeter oftrianglewithsides29,37,  49  =115 | 115 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 29 + 37 + 49 = 115 | 
| 
	(2)** (3)  =  8 | 8 | 
	Step 1: Compute 2 ** 3.
Step 2: The result is 8. | 
| 
	11  -  77=  -66 | -66 | 
	Step 1: Compute 11 - 77.
Step 2: The result is -66. | 
| 
	80*  44=  3520 | 3,520 | 
	Step 1: Compute 80 * 44.
Step 2: The result is 3520. | 
| 
	56  /8  = 7 | 7 | 
	Step 1: Compute 56 / 8.
Step 2: The result is 7. | 
| 
	7 **  (4)  = 2401 | 2,401 | 
	Step 1: Compute 7 ** 4.
Step 2: The result is 2401. | 
| 
	4 ** 4= 256 | 256 | 
	Step 1: Compute 4 ** 4.
Step 2: The result is 256. | 
| 
	(70)  +  58= 128 | 128 | 
	Step 1: Compute 70 + 58.
Step 2: The result is 128. | 
| 
	perimeteroftriangle withsides 31,  24, 22  =77 | 77 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 31 + 24 + 22 = 77 | 
| 
	perimeterof rectangle with width  6and  height 43 =  98 | 98 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (6 + 43) = 2 × 49 = 98 | 
| 
	perimeter of  trianglewithsides9,  11, 38 = 58 | 58 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 9 + 11 + 38 = 58 | 
| 
	perimeter ofrectanglewith width2 and height 32  =  68 | 68 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (2 + 32) = 2 × 34 = 68 | 
| 
	area  of rectanglewith width22  and  height9=198 | 198 | 
	Step 1: Area formula is width × height.
Step 2: 22 × 9 = 198 | 
| 
	perimeterof  triangle with  sides 49,  28,  34=111 | 111 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 49 + 28 + 34 = 111 | 
| 
	perimeter of circlewith  radius11  = 69.12 | 69.12 | 
	Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 11 = 69.12 | 
| 
	perimeter ofrectangle  withwidth 28  and  height  31  = 118 | 118 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (28 + 31) = 2 × 59 = 118 | 
| 
	66  *(81)= 5346 | 5,346 | 
	Step 1: Compute 66 * 81.
Step 2: The result is 5346. | 
| 
	perimeter  of  circlewith radius  17=106.81 | 106.81 | 
	Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 17 = 106.81 | 
| 
	54 / 18=3 | 3 | 
	Step 1: Compute 54 / 18.
Step 2: The result is 3. | 
| 
	29 %  15=14 | 14 | 
	Step 1: Compute 29 % 15.
Step 2: The result is 14. | 
| 
	perimeter  of rectanglewith width  40  and  height22  =  124 | 124 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (40 + 22) = 2 × 62 = 124 | 
| 
	areaofcirclewith  radius 2= 12.57 | 12.57 | 
	Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57 | 
| 
	(3) -  75 =  -72 | -72 | 
	Step 1: Compute 3 - 75.
Step 2: The result is -72. | 
| 
	2**(2)= 4 | 4 | 
	Step 1: Compute 2 ** 2.
Step 2: The result is 4. | 
| 
	area of circle  with radius17  = 907.92 | 907.92 | 
	Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92 | 
| 
	area of rectanglewith  width40  and  height  13  =520 | 520 | 
	Step 1: Area formula is width × height.
Step 2: 40 × 13 = 520 | 
| 
	area  ofrectanglewith width  49 and  height  41= 2009 | 2,009 | 
	Step 1: Area formula is width × height.
Step 2: 49 × 41 = 2009 | 
| 
	area  of  circle with radius1 =  3.14 | 3.14 | 
	Step 1: Area formula is π × r².
Step 2: π × 1² = 3.14 × 1 = 3.14 | 
| 
	area  of rectanglewith width 15andheight  35 =  525 | 525 | 
	Step 1: Area formula is width × height.
Step 2: 15 × 35 = 525 | 
| 
	perimeter  of circlewith radius  3=18.85 | 18.85 | 
	Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 3 = 18.85 | 
| 
	perimeter  of circlewithradius17 =  106.81 | 106.81 | 
	Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 17 = 106.81 | 
| 
	areaoftriangle withbase16 andheight  50  = 400.00 | 400 | 
	Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 16 × 50 = 400.00 | 
| 
	perimeter  of  circlewith radius  10  =62.83 | 62.83 | 
	Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83 | 
| 
	(3) /  (3)  =1 | 1 | 
	Step 1: Compute 3 / 3.
Step 2: The result is 1. | 
| 
	25-39=  -14 | -14 | 
	Step 1: Compute 25 - 39.
Step 2: The result is -14. | 
| 
	32- 80  =-48 | -48 | 
	Step 1: Compute 32 - 80.
Step 2: The result is -48. | 
| 
	hypotenuseof  righttriangle with  legs  4  and  30  =  30.27 | 30.27 | 
	Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(4² + 30²) = sqrt(16 + 900) = sqrt(916) = 30.27 | 
| 
	36/  (9)= 4 | 4 | 
	Step 1: Compute 36 / 9.
Step 2: The result is 4. | 
| 
	areaoftrianglewithbase 45 and  height 21=472.50 | 472.5 | 
	Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 45 × 21 = 472.50 | 
| 
	area oftriangle  with base50and  height  48  =  1200.00 | 1,200 | 
	Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 50 × 48 = 1200.00 | 
| 
	(40)  /8  =5 | 5 | 
	Step 1: Compute 40 / 8.
Step 2: The result is 5. | 
| 
	perimeter  ofcircle  with  radius  20  =  125.66 | 125.66 | 
	Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 20 = 125.66 | 
| 
	area of rectangle  with  width 36 andheight  2= 72 | 72 | 
	Step 1: Area formula is width × height.
Step 2: 36 × 2 = 72 | 
| 
	(90)/ 9  =  10 | 10 | 
	Step 1: Compute 90 / 9.
Step 2: The result is 10. | 
| 
	areaof circle with  radius  12=452.39 | 452.39 | 
	Step 1: Area formula is π × r².
Step 2: π × 12² = 3.14 × 144 = 452.39 | 
| 
	hypotenuse of  right triangle  with legs 1and12=12.04 | 12.04 | 
	Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(1² + 12²) = sqrt(1 + 144) = sqrt(145) = 12.04 | 
| 
	68  /  17=4 | 4 | 
	Step 1: Compute 68 / 17.
Step 2: The result is 4. | 
| 
	5  **3=125 | 125 | 
	Step 1: Compute 5 ** 3.
Step 2: The result is 125. | 
| 
	79  +  10 = 89 | 89 | 
	Step 1: Compute 79 + 10.
Step 2: The result is 89. | 
| 
	area of  rectanglewith width 18andheight 37 =666 | 666 | 
	Step 1: Area formula is width × height.
Step 2: 18 × 37 = 666 | 
| 
	7 **  3=343 | 343 | 
	Step 1: Compute 7 ** 3.
Step 2: The result is 343. | 
| 
	70  % (18)  =  16 | 16 | 
	Step 1: Compute 70 % 18.
Step 2: The result is 16. | 
| 
	perimeterof  trianglewith  sides5, 43, 24= 72 | 72 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 5 + 43 + 24 = 72 | 
| 
	108 / 18 = 6 | 6 | 
	Step 1: Compute 108 / 18.
Step 2: The result is 6. | 
| 
	80 -71= 9 | 9 | 
	Step 1: Compute 80 - 71.
Step 2: The result is 9. | 
| 
	25 + 67  =92 | 92 | 
	Step 1: Compute 25 + 67.
Step 2: The result is 92. | 
| 
	8 **4  =  4096 | 4,096 | 
	Step 1: Compute 8 ** 4.
Step 2: The result is 4096. | 
			Subsets and Splits
				
	
				
			
				
No community queries yet
The top public SQL queries from the community will appear here once available.
