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Math-2

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1
Expression
stringlengths
5
66
Result
float64
-99
10k
Steps
stringlengths
47
107
(20) + (9) =29
29
Step 1: Compute 20 + 9. Step 2: The result is 29.
16/(4) = 4
4
Step 1: Compute 16 / 4. Step 2: The result is 4.
area of circlewith radius11 = 380.13
380.13
Step 1: Area formula is π × r². Step 2: π × 11² = 3.14 × 121 = 380.13
(13)-95= -82
-82
Step 1: Compute 13 - 95. Step 2: The result is -82.
perimeter ofrectangle with width 42 and height8= 100
100
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (42 + 8) = 2 × 50 = 100
5**4 = 625
625
Step 1: Compute 5 ** 4. Step 2: The result is 625.
(43)+4 =47
47
Step 1: Compute 43 + 4. Step 2: The result is 47.
perimeter of rectangle with width10andheight12= 44
44
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (10 + 12) = 2 × 22 = 44
90/10 = 9
9
Step 1: Compute 90 / 10. Step 2: The result is 9.
171/ (19) = 9
9
Step 1: Compute 171 / 19. Step 2: The result is 9.
hypotenuse of right triangle with legs 3 and 28=28.16
28.16
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(3² + 28²) = sqrt(9 + 784) = sqrt(793) = 28.16
perimeter oftriangle with sides 11, 43, 29=83
83
Step 1: Perimeter formula is a + b + c. Step 2: 11 + 43 + 29 = 83
84 - 18 = 66
66
Step 1: Compute 84 - 18. Step 2: The result is 66.
(46) * 45=2070
2,070
Step 1: Compute 46 * 45. Step 2: The result is 2070.
(14) - 55 =-41
-41
Step 1: Compute 14 - 55. Step 2: The result is -41.
areaof triangle with base 15 andheight 6= 45.00
45
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 15 × 6 = 45.00
(32)+(100)= 132
132
Step 1: Compute 32 + 100. Step 2: The result is 132.
10 ** (2) = 100
100
Step 1: Compute 10 ** 2. Step 2: The result is 100.
hypotenuse of righttriangle with legs 5 and 22 =22.56
22.56
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(5² + 22²) = sqrt(25 + 484) = sqrt(509) = 22.56
area of rectanglewithwidth46 and height48 = 2208
2,208
Step 1: Area formula is width × height. Step 2: 46 × 48 = 2208
area of circle with radius16= 804.25
804.25
Step 1: Area formula is π × r². Step 2: π × 16² = 3.14 × 256 = 804.25
perimeter of triangle with sides 27, 4, 43 = 74
74
Step 1: Perimeter formula is a + b + c. Step 2: 27 + 4 + 43 = 74
areaofcircle withradius 10 =314.16
314.16
Step 1: Area formula is π × r². Step 2: π × 10² = 3.14 × 100 = 314.16
area of circle withradius 10 =314.16
314.16
Step 1: Area formula is π × r². Step 2: π × 10² = 3.14 × 100 = 314.16
hypotenuseof right trianglewith legs27 and 21 =34.21
34.21
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(27² + 21²) = sqrt(729 + 441) = sqrt(1170) = 34.21
hypotenuseof righttriangle with legs 25 and 20 = 32.02
32.02
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(25² + 20²) = sqrt(625 + 400) = sqrt(1025) = 32.02
9 ** 2 = 81
81
Step 1: Compute 9 ** 2. Step 2: The result is 81.
hypotenuse of righttriangle with legs 3 and 13 = 13.34
13.34
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(3² + 13²) = sqrt(9 + 169) = sqrt(178) = 13.34
perimeteroftriangle with sides24, 38, 1= 63
63
Step 1: Perimeter formula is a + b + c. Step 2: 24 + 38 + 1 = 63
74 - 59 =15
15
Step 1: Compute 74 - 59. Step 2: The result is 15.
(8) ** (4) = 4096
4,096
Step 1: Compute 8 ** 4. Step 2: The result is 4096.
hypotenuse of righttrianglewithlegs25 and 1= 25.02
25.02
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(25² + 1²) = sqrt(625 + 1) = sqrt(626) = 25.02
area ofcircle with radius 15 =706.86
706.86
Step 1: Area formula is π × r². Step 2: π × 15² = 3.14 × 225 = 706.86
perimeterofrectanglewithwidth41and height 19 =120
120
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (41 + 19) = 2 × 60 = 120
hypotenuseofright triangle with legs 5 and 11 = 12.08
12.08
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(5² + 11²) = sqrt(25 + 121) = sqrt(146) = 12.08
areaof circle with radius3 = 28.27
28.27
Step 1: Area formula is π × r². Step 2: π × 3² = 3.14 × 9 = 28.27
2** 2= 4
4
Step 1: Compute 2 ** 2. Step 2: The result is 4.
perimeterof rectanglewith width 27 andheight 42 =138
138
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (27 + 42) = 2 × 69 = 138
perimeter of circlewith radius 10=62.83
62.83
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 10 = 62.83
170 / 17 = 10
10
Step 1: Compute 170 / 17. Step 2: The result is 10.
perimeter ofcircle with radius1 =6.28
6.28
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 1 = 6.28
(41) % 19 = 3
3
Step 1: Compute 41 % 19. Step 2: The result is 3.
hypotenuse ofrighttriangle with legs 18and15 = 23.43
23.43
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(18² + 15²) = sqrt(324 + 225) = sqrt(549) = 23.43
areaof circle withradius5=78.54
78.54
Step 1: Area formula is π × r². Step 2: π × 5² = 3.14 × 25 = 78.54
74% 9 = 2
2
Step 1: Compute 74 % 9. Step 2: The result is 2.
9 % 4 =1
1
Step 1: Compute 9 % 4. Step 2: The result is 1.
(34) +(48) =82
82
Step 1: Compute 34 + 48. Step 2: The result is 82.
50-86= -36
-36
Step 1: Compute 50 - 86. Step 2: The result is -36.
area of circlewith radius 1= 3.14
3.14
Step 1: Area formula is π × r². Step 2: π × 1² = 3.14 × 1 = 3.14
hypotenuse of righttriangle with legs 21 and7= 22.14
22.14
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(21² + 7²) = sqrt(441 + 49) = sqrt(490) = 22.14
perimeterofrectangle withwidth 17and height 45 =124
124
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (17 + 45) = 2 × 62 = 124
28-32 = -4
-4
Step 1: Compute 28 - 32. Step 2: The result is -4.
74* 47 = 3478
3,478
Step 1: Compute 74 * 47. Step 2: The result is 3478.
(12)/3 = 4
4
Step 1: Compute 12 / 3. Step 2: The result is 4.
87 %3 = 0
0
Step 1: Compute 87 % 3. Step 2: The result is 0.
54- 57= -3
-3
Step 1: Compute 54 - 57. Step 2: The result is -3.
74 * 26=1924
1,924
Step 1: Compute 74 * 26. Step 2: The result is 1924.
4** 4=256
256
Step 1: Compute 4 ** 4. Step 2: The result is 256.
area of circle withradius 17= 907.92
907.92
Step 1: Area formula is π × r². Step 2: π × 17² = 3.14 × 289 = 907.92
area of rectanglewith width38 andheight 13= 494
494
Step 1: Area formula is width × height. Step 2: 38 × 13 = 494
hypotenuseof righttriangle with legs 12 and 10= 15.62
15.62
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(12² + 10²) = sqrt(144 + 100) = sqrt(244) = 15.62
perimeter of triangle withsides 40,39, 33= 112
112
Step 1: Perimeter formula is a + b + c. Step 2: 40 + 39 + 33 = 112
86 % (3)= 2
2
Step 1: Compute 86 % 3. Step 2: The result is 2.
(1) ** (3)= 1
1
Step 1: Compute 1 ** 3. Step 2: The result is 1.
(73) * (92)= 6716
6,716
Step 1: Compute 73 * 92. Step 2: The result is 6716.
hypotenuseof right triangle with legs 29and 25 = 38.29
38.29
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(29² + 25²) = sqrt(841 + 625) = sqrt(1466) = 38.29
perimeter oftriangle with sides 5, 45,4 = 54
54
Step 1: Perimeter formula is a + b + c. Step 2: 5 + 45 + 4 = 54
perimeter ofrectangle with width 40andheight 48 = 176
176
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (40 + 48) = 2 × 88 = 176
10 /1 = 10
10
Step 1: Compute 10 / 1. Step 2: The result is 10.
area of triangle with base25 and height33 = 412.50
412.5
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 25 × 33 = 412.50
(6)*43= 258
258
Step 1: Compute 6 * 43. Step 2: The result is 258.
9 ** 4= 6561
6,561
Step 1: Compute 9 ** 4. Step 2: The result is 6561.
98 - (76)=22
22
Step 1: Compute 98 - 76. Step 2: The result is 22.
hypotenuseofright triangle with legs 26and 11 = 28.23
28.23
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(26² + 11²) = sqrt(676 + 121) = sqrt(797) = 28.23
(17) -44=-27
-27
Step 1: Compute 17 - 44. Step 2: The result is -27.
38 +15 = 53
53
Step 1: Compute 38 + 15. Step 2: The result is 53.
area ofrectangle withwidth 8 andheight36 =288
288
Step 1: Area formula is width × height. Step 2: 8 × 36 = 288
area of triangle with base39andheight 43 = 838.50
838.5
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 39 × 43 = 838.50
7** 4 =2401
2,401
Step 1: Compute 7 ** 4. Step 2: The result is 2401.
(9) **4 =6561
6,561
Step 1: Compute 9 ** 4. Step 2: The result is 6561.
perimeterof circlewith radius 10 = 62.83
62.83
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 10 = 62.83
99 - 73= 26
26
Step 1: Compute 99 - 73. Step 2: The result is 26.
47 + (10) = 57
57
Step 1: Compute 47 + 10. Step 2: The result is 57.
30 /(5)= 6
6
Step 1: Compute 30 / 5. Step 2: The result is 6.
areaoftrianglewithbase32and height 8 = 128.00
128
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 32 × 8 = 128.00
hypotenuse of right triangle withlegs 11 and29= 31.02
31.02
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(11² + 29²) = sqrt(121 + 841) = sqrt(962) = 31.02
perimeter of circle withradius17 =106.81
106.81
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 17 = 106.81
126 / 18= 7
7
Step 1: Compute 126 / 18. Step 2: The result is 7.
perimeter of triangle withsides42, 14, 49 = 105
105
Step 1: Perimeter formula is a + b + c. Step 2: 42 + 14 + 49 = 105
hypotenuse ofright triangle withlegs 25 and26 = 36.07
36.07
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(25² + 26²) = sqrt(625 + 676) = sqrt(1301) = 36.07
67 + 1 = 68
68
Step 1: Compute 67 + 1. Step 2: The result is 68.
perimeter oftriangle with sides 50, 23, 26= 99
99
Step 1: Perimeter formula is a + b + c. Step 2: 50 + 23 + 26 = 99
45+38 = 83
83
Step 1: Compute 45 + 38. Step 2: The result is 83.
area of circlewith radius 10= 314.16
314.16
Step 1: Area formula is π × r². Step 2: π × 10² = 3.14 × 100 = 314.16
24+ 7 = 31
31
Step 1: Compute 24 + 7. Step 2: The result is 31.
(100) % 15= 10
10
Step 1: Compute 100 % 15. Step 2: The result is 10.
(7) * 22= 154
154
Step 1: Compute 7 * 22. Step 2: The result is 154.
2 * 5 =10
10
Step 1: Compute 2 * 5. Step 2: The result is 10.
5 ** 4 =625
625
Step 1: Compute 5 ** 4. Step 2: The result is 625.
area ofcircle withradius 1=3.14
3.14
Step 1: Area formula is π × r². Step 2: π × 1² = 3.14 × 1 = 3.14