| Expression
				 stringlengths 5 66 | Result
				 float64 -99 10k | Steps
				 stringlengths 47 107 | 
|---|---|---|
| 
	35  /(7)=5 | 5 | 
	Step 1: Compute 35 / 7.
Step 2: The result is 5. | 
| 
	area of  circle with  radius 3 = 28.27 | 28.27 | 
	Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27 | 
| 
	(51) %1  = 0 | 0 | 
	Step 1: Compute 51 % 1.
Step 2: The result is 0. | 
| 
	perimeter  ofrectanglewith width  13 andheight  47 =120 | 120 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (13 + 47) = 2 × 60 = 120 | 
| 
	perimeter ofrectangle withwidth 9andheight  50=  118 | 118 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (9 + 50) = 2 × 59 = 118 | 
| 
	(18) *  (15) =  270 | 270 | 
	Step 1: Compute 18 * 15.
Step 2: The result is 270. | 
| 
	1** (4) = 1 | 1 | 
	Step 1: Compute 1 ** 4.
Step 2: The result is 1. | 
| 
	57  - 61 = -4 | -4 | 
	Step 1: Compute 57 - 61.
Step 2: The result is -4. | 
| 
	68-  (55)=13 | 13 | 
	Step 1: Compute 68 - 55.
Step 2: The result is 13. | 
| 
	85*77 =6545 | 6,545 | 
	Step 1: Compute 85 * 77.
Step 2: The result is 6545. | 
| 
	areaofcirclewithradius  2= 12.57 | 12.57 | 
	Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57 | 
| 
	area  oftriangle with  base  48and height39=  936.00 | 936 | 
	Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 48 × 39 = 936.00 | 
| 
	67  +  (46)= 113 | 113 | 
	Step 1: Compute 67 + 46.
Step 2: The result is 113. | 
| 
	26  *  (12) = 312 | 312 | 
	Step 1: Compute 26 * 12.
Step 2: The result is 312. | 
| 
	area ofcircle  withradius6=  113.10 | 113.1 | 
	Step 1: Area formula is π × r².
Step 2: π × 6² = 3.14 × 36 = 113.10 | 
| 
	perimeterofcircle  with radius8  = 50.27 | 50.27 | 
	Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 8 = 50.27 | 
| 
	14/ (14)  =1 | 1 | 
	Step 1: Compute 14 / 14.
Step 2: The result is 1. | 
| 
	(75) * 30 =  2250 | 2,250 | 
	Step 1: Compute 75 * 30.
Step 2: The result is 2250. | 
| 
	area  of rectangle  withwidth 26and height  15=  390 | 390 | 
	Step 1: Area formula is width × height.
Step 2: 26 × 15 = 390 | 
| 
	hypotenuse  of  righttriangle  with  legs 25and  15 =  29.15 | 29.15 | 
	Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(25² + 15²) = sqrt(625 + 225) = sqrt(850) = 29.15 | 
| 
	area  of circle with  radius 17 =  907.92 | 907.92 | 
	Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92 | 
| 
	6**4=  1296 | 1,296 | 
	Step 1: Compute 6 ** 4.
Step 2: The result is 1296. | 
| 
	area  of triangle with  base 5  and  height28  = 70.00 | 70 | 
	Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 5 × 28 = 70.00 | 
| 
	15- (73)  =  -58 | -58 | 
	Step 1: Compute 15 - 73.
Step 2: The result is -58. | 
| 
	perimeter  of  triangle  withsides29,16, 31= 76 | 76 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 29 + 16 + 31 = 76 | 
| 
	area  of triangle with base  36  and  height9  = 162.00 | 162 | 
	Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 36 × 9 = 162.00 | 
| 
	perimeterofrectanglewith  width 49  andheight 16 = 130 | 130 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (49 + 16) = 2 × 65 = 130 | 
| 
	hypotenuse ofright triangle  withlegs 19  and16  = 24.84 | 24.84 | 
	Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(19² + 16²) = sqrt(361 + 256) = sqrt(617) = 24.84 | 
| 
	82 -2 = 80 | 80 | 
	Step 1: Compute 82 - 2.
Step 2: The result is 80. | 
| 
	80/  20  =  4 | 4 | 
	Step 1: Compute 80 / 20.
Step 2: The result is 4. | 
| 
	49  +  86  =  135 | 135 | 
	Step 1: Compute 49 + 86.
Step 2: The result is 135. | 
| 
	area of trianglewithbase  46  and height 20= 460.00 | 460 | 
	Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 46 × 20 = 460.00 | 
| 
	(51)  %15=6 | 6 | 
	Step 1: Compute 51 % 15.
Step 2: The result is 6. | 
| 
	(88)%  12  =4 | 4 | 
	Step 1: Compute 88 % 12.
Step 2: The result is 4. | 
| 
	areaof  triangle  with  base 16and  height 13= 104.00 | 104 | 
	Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 16 × 13 = 104.00 | 
| 
	60 +  2=  62 | 62 | 
	Step 1: Compute 60 + 2.
Step 2: The result is 62. | 
| 
	100 - 23  =  77 | 77 | 
	Step 1: Compute 100 - 23.
Step 2: The result is 77. | 
| 
	perimeter ofrectangle with width 33and height 12 = 90 | 90 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (33 + 12) = 2 × 45 = 90 | 
| 
	area  ofrectangle withwidth18  andheight 30 =  540 | 540 | 
	Step 1: Area formula is width × height.
Step 2: 18 × 30 = 540 | 
| 
	perimeter  of  triangle withsides  50,2, 8 = 60 | 60 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 50 + 2 + 8 = 60 | 
| 
	areaof  circle with radius  19  =1134.11 | 1,134.11 | 
	Step 1: Area formula is π × r².
Step 2: π × 19² = 3.14 × 361 = 1134.11 | 
| 
	area  of rectangle  with  width41  and  height  17 =  697 | 697 | 
	Step 1: Area formula is width × height.
Step 2: 41 × 17 = 697 | 
| 
	(4)%5 =4 | 4 | 
	Step 1: Compute 4 % 5.
Step 2: The result is 4. | 
| 
	3 **  2=  9 | 9 | 
	Step 1: Compute 3 ** 2.
Step 2: The result is 9. | 
| 
	47  %(9) =2 | 2 | 
	Step 1: Compute 47 % 9.
Step 2: The result is 2. | 
| 
	perimeterof rectangle withwidth6  andheight 33 =78 | 78 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (6 + 33) = 2 × 39 = 78 | 
| 
	6  **3  = 216 | 216 | 
	Step 1: Compute 6 ** 3.
Step 2: The result is 216. | 
| 
	29+84=  113 | 113 | 
	Step 1: Compute 29 + 84.
Step 2: The result is 113. | 
| 
	area ofcircle  with radius  1=3.14 | 3.14 | 
	Step 1: Area formula is π × r².
Step 2: π × 1² = 3.14 × 1 = 3.14 | 
| 
	45/ 5  =9 | 9 | 
	Step 1: Compute 45 / 5.
Step 2: The result is 9. | 
| 
	perimeter  of rectanglewith  width  47 andheight18 =130 | 130 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (47 + 18) = 2 × 65 = 130 | 
| 
	area of  rectangle with  width43  andheight13=  559 | 559 | 
	Step 1: Area formula is width × height.
Step 2: 43 × 13 = 559 | 
| 
	area  of rectangle  withwidth 6  and height 31 =186 | 186 | 
	Step 1: Area formula is width × height.
Step 2: 6 × 31 = 186 | 
| 
	26- 19 =  7 | 7 | 
	Step 1: Compute 26 - 19.
Step 2: The result is 7. | 
| 
	14  %12= 2 | 2 | 
	Step 1: Compute 14 % 12.
Step 2: The result is 2. | 
| 
	(60) /  15  =  4 | 4 | 
	Step 1: Compute 60 / 15.
Step 2: The result is 4. | 
| 
	(32)  /8  =  4 | 4 | 
	Step 1: Compute 32 / 8.
Step 2: The result is 4. | 
| 
	perimeter  ofrectangle with  width28  andheight  42 =140 | 140 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (28 + 42) = 2 × 70 = 140 | 
| 
	1 **  4 =  1 | 1 | 
	Step 1: Compute 1 ** 4.
Step 2: The result is 1. | 
| 
	perimeter  of triangle  with sides25, 46,31 = 102 | 102 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 25 + 46 + 31 = 102 | 
| 
	140 /14  = 10 | 10 | 
	Step 1: Compute 140 / 14.
Step 2: The result is 10. | 
| 
	area  of  trianglewith  base 23  and height24  = 276.00 | 276 | 
	Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 23 × 24 = 276.00 | 
| 
	81 -  (68)=13 | 13 | 
	Step 1: Compute 81 - 68.
Step 2: The result is 13. | 
| 
	areaof  trianglewith  base 36and  height 8=  144.00 | 144 | 
	Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 36 × 8 = 144.00 | 
| 
	47 * (86) =  4042 | 4,042 | 
	Step 1: Compute 47 * 86.
Step 2: The result is 4042. | 
| 
	perimeteroftriangle  withsides39,  42,  37 =  118 | 118 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 39 + 42 + 37 = 118 | 
| 
	7  ** 2  = 49 | 49 | 
	Step 1: Compute 7 ** 2.
Step 2: The result is 49. | 
| 
	89 * 83  =7387 | 7,387 | 
	Step 1: Compute 89 * 83.
Step 2: The result is 7387. | 
| 
	70+49  =  119 | 119 | 
	Step 1: Compute 70 + 49.
Step 2: The result is 119. | 
| 
	56 *  (87)  =  4872 | 4,872 | 
	Step 1: Compute 56 * 87.
Step 2: The result is 4872. | 
| 
	perimeter  ofrectanglewith width19 and height 43=  124 | 124 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (19 + 43) = 2 × 62 = 124 | 
| 
	perimeterof triangle with sides50,44,22 = 116 | 116 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 50 + 44 + 22 = 116 | 
| 
	48/ 12=4 | 4 | 
	Step 1: Compute 48 / 12.
Step 2: The result is 4. | 
| 
	52%7= 3 | 3 | 
	Step 1: Compute 52 % 7.
Step 2: The result is 3. | 
| 
	hypotenuseof right  trianglewithlegs19and  27 =33.02 | 33.02 | 
	Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(19² + 27²) = sqrt(361 + 729) = sqrt(1090) = 33.02 | 
| 
	83  +  25=108 | 108 | 
	Step 1: Compute 83 + 25.
Step 2: The result is 108. | 
| 
	perimeter of circlewith radius16  = 100.53 | 100.53 | 
	Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 16 = 100.53 | 
| 
	24 / 6 =  4 | 4 | 
	Step 1: Compute 24 / 6.
Step 2: The result is 4. | 
| 
	area  of  circle with radius 11=380.13 | 380.13 | 
	Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13 | 
| 
	72/9  =  8 | 8 | 
	Step 1: Compute 72 / 9.
Step 2: The result is 8. | 
| 
	area ofcircle with  radius  5  = 78.54 | 78.54 | 
	Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54 | 
| 
	area  of circlewithradius  5= 78.54 | 78.54 | 
	Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54 | 
| 
	perimeter of  rectanglewith width 18  and height23=  82 | 82 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (18 + 23) = 2 × 41 = 82 | 
| 
	perimeter of circlewith  radius16 =  100.53 | 100.53 | 
	Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 16 = 100.53 | 
| 
	67% (13)  = 2 | 2 | 
	Step 1: Compute 67 % 13.
Step 2: The result is 2. | 
| 
	perimeterof circle  with  radius 3=  18.85 | 18.85 | 
	Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 3 = 18.85 | 
| 
	perimeter ofrectangle  withwidth  18  andheight  16= 68 | 68 | 
	Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (18 + 16) = 2 × 34 = 68 | 
| 
	20  -  69= -49 | -49 | 
	Step 1: Compute 20 - 69.
Step 2: The result is -49. | 
| 
	78+ 38= 116 | 116 | 
	Step 1: Compute 78 + 38.
Step 2: The result is 116. | 
| 
	perimeter of triangle with sides14,  17, 32= 63 | 63 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 14 + 17 + 32 = 63 | 
| 
	hypotenuse of  righttrianglewith  legs  6  and14 =  15.23 | 15.23 | 
	Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(6² + 14²) = sqrt(36 + 196) = sqrt(232) = 15.23 | 
| 
	hypotenuseofrighttriangle withlegs 12 and  23=25.94 | 25.94 | 
	Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(12² + 23²) = sqrt(144 + 529) = sqrt(673) = 25.94 | 
| 
	perimeterof  triangle withsides35,20,  43  =  98 | 98 | 
	Step 1: Perimeter formula is a + b + c.
Step 2: 35 + 20 + 43 = 98 | 
| 
	perimeterofcirclewith radius  13  =  81.68 | 81.68 | 
	Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 13 = 81.68 | 
| 
	area  of circlewith radius 14  =  615.75 | 615.75 | 
	Step 1: Area formula is π × r².
Step 2: π × 14² = 3.14 × 196 = 615.75 | 
| 
	43* 36 = 1548 | 1,548 | 
	Step 1: Compute 43 * 36.
Step 2: The result is 1548. | 
| 
	(74)%3=  2 | 2 | 
	Step 1: Compute 74 % 3.
Step 2: The result is 2. | 
| 
	(58)  %  10=8 | 8 | 
	Step 1: Compute 58 % 10.
Step 2: The result is 8. | 
| 
	areaof  circle with  radius  7  = 153.94 | 153.94 | 
	Step 1: Area formula is π × r².
Step 2: π × 7² = 3.14 × 49 = 153.94 | 
| 
	77  -66 = 11 | 11 | 
	Step 1: Compute 77 - 66.
Step 2: The result is 11. | 
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